<u>Answer:</u> The given example is a physical change.
<u>Explanation:</u>
A chemical change is defined as the change in which chemical composition of a substance changes and results in the formation of a new substance. These are usually irreversible process.
A physical change is defined as the change in which only the shape and size of the substance changes and no new substance is formed. Only phase change occurs in these processes. These are usually considered as a reversible change.
For the given example: Moisture in the air forms beads of water on a cold window pane.
This is a physical change because water was initially present in the gaseous state (Moisture in the air) and when it is coming in contact with the cold window pane, the gaseous state of water gets converted into a liquid state.
Hence, the given example is a physical change.
Answer:
Any binary molecular compound of hydrogen and a Group 6A element above Selenium will be less acidic, so water and dihydrogen sulfide are less acidic in aqueous solution than hydrogen selenide.
Explanation:
Going down in a group increases the atomic radius and a greater atomic radius implyes greater ionic radius.
When ionization takes place in these compounds they yelds protons (hidrogen ion) and an lewis base (anion). The greater the ionic radius the greater its stability, thus the periodic tendency is increaing the acidity of binary hidrogen compounds when going down a group. On the other hand going up a group decreases acidity, so any molecular compound of hydrogen and a Group 6A element above Selenium will be less acidic, so water and dihydrogen sulfide are less acidic in aqueous solution than hydrogen selenide.
Answer:
answer is 1.A measurment of the...
Answer:
B. 13.7 mm
Explanation:
by similarity of rectangular triangles, we have:
(1) Δ ABC and Δ AB'C'
∴ AB/AB' = AC/AC'
∴ hypotenuse (AB)² = AC² + BC².....Pythagorean theorem
⇒ AB² = (51 mm)² + (13 mm)²
⇒ AB² = 2770 mm²
⇒ AB = 52.63 mm
(2) Δ AB'C' :
∴ hypotenuse (AB')² = AC'² + B'C'²
∴ B'C' = 3.5 mm
from (1):
⇒ AB' = (AB)(AC') / AC = (52.63)(AC') / (51 mm)
⇒ AB' = 1.032AC'.......(3)
(3) in (2):
⇒ (1.032AC')² = AC'² + (3.5)²
⇒1.065AC'² = AC'² + 12.25
⇒ 0.065AC'² = 12.25
⇒ AC'² = 188.462
⇒ AC' = √188.462
⇒ AC' = 13.72 mm
Answer:
umm...what is the question though?
Explanation:
