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AfilCa [17]
3 years ago
10

Which important change in electronic devices, such as televisions and computers, is a result of the use of metalloids as semicon

ductors?
A) Electronic devices have become smaller.
B) Electronic devices are now more brittle.
C) Electronic devices now use more energy.
D) Electronic devices have become more expensive.
Chemistry
2 answers:
nalin [4]3 years ago
8 0

Answer:

option A

Explanation:

correct answer is option A

metalloids are the substances which are not metal and also are not non-metal they have the property of both metals and non-metals.                                                  

metalloids example are silicon, Germanium, Arsenic (As) etc.

Usage of metalloids as semiconductor has  decreases the size of the circuits which leads to the shrink the size of many electronic devices such as TV, mobile etc.

scZoUnD [109]3 years ago
7 0

Answer:

Option (A) Electronic devices have become smaller.

Explanation:

Semiconductor devices are the devices which are based on the properties of the  semiconductor materials like  germanium, silicon, gallium and arsenide. The commonly used materials in electronic devices are the silicon and  germanium because of their low cut off voltages i.e 0.7 v and 0.3 v. Semiconductor materials made the electronic devices smaller as they replaced the Vacuum tubes which was bulky with high operating voltage, high power consumption.

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Atoms are the smallest particles of a compound that still retain the properties of that
N76 [4]

Answer:

the answer is true

Explanation:

it is the smallest particle in an element that takes part in a chemical reaction

5 0
3 years ago
For the following pairs of ions, use the concept that a chemical compound must have a net charge of zero to predict the formula
Dafna11 [192]

\\ \sf\longmapsto FeP

\\ \sf\longmapsto Fe_2S_3

\\ \sf\longmapsto FeCl_2

\\ \sf\longmapsto MgCl_2

\\ \sf\longmapsto MgO

\\ \sf\longmapsto Mg_3N_2

\\ \sf\longmapsto Na_3P

\\ \sf\longmapsto Na_2S

\\ \sf\longmapsto CoO

\\ \sf\longmapsto Co_2S_3

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4 0
3 years ago
Given the following information, what is the concentration of H2O(g) at equilibrium? [H2S](eq) = 0.671 M [O2](eq) = 0.587 M Kc =
MAVERICK [17]

<u>Answer:</u> The equilibrium concentration of water is 0.597 M

<u>Explanation:</u>

Equilibrium constant in terms of concentration is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K_{c}

For a general chemical reaction:

aA+bB\rightleftharpoons cC+dD

The expression for K_{eq} is written as:

K_{c}=\frac{[C]^c[D]^d}{[A]^a[B]^b}

The concentration of pure solids and pure liquids are taken as 1 in the expression.

For the given chemical reaction:

2H_2S(g)+O_2(g)\rightleftharpoons 2S(s)+2H_2O(g)

The expression of K_c for above equation is:

K_c=\frac{[H_2O]^2}{[H_2S]^2\times [O_2]}

We are given:

[H_2S]_{eq}=0.671M

[O_2]_{eq}=0.587M

K_c=1.35

Putting values in above expression, we get:

1.35=\frac{[H_2O]^2}{(0.671)^2\times 0.587}

[H_2O]=\sqrt{(1.35\times 0.671\times 0.671\times 0.587)}=0.597M

Hence, the equilibrium concentration of water is 0.597 M

8 0
4 years ago
g For the following reaction, 0.500 moles of silver nitrate are mixed with 0.285 moles of copper(II) chloride. What is the formu
scZoUnD [109]

Answer:

CuCl_2 is the formula for the limiting reagent.

Mass of silver chloride produced is 71.8 g.

Explanation:

CuCl_2+2AgNO_3\rightarrow 2AgCl+Cu(NO_3)_2

Moles of silver nitrate = 0.500 mol

Moles of copper(II) chloride = 0.285 mol

According to reaction, 2 moles of silver nitrate reacts with 1 mole of copper chloride , then 0.500 mole of silver nitrate will react with :

\frac{1}{2}\times 0.500 mol=0.250 mol of copper(II) chloride

As we can see that moles of copper(II) chloride will be reacting is 0.250 mol less than present moles of copper (II) chloride ,so this means that silver nitrate is limiting reagent.

And moles of silver chloride to be formed will depend upon silver nitrate.

According to reaction, 2 moles of silver nitrate gives 2 moles of silver chloride , then 0.500 mole of silver nitrate will give  :

\frac{2}{2}\times 0.500 mol=0.500 mol of silver chloride

Mass of silver chloride produced:

0.500 mol × 143.5 g/mol = 71.8 g

7 0
3 years ago
Which type of reactions form salts?
s344n2d4d5 [400]

Neutralization reactions are the reactions type which form salts.

Explanation:

Salts are formed by ionic bonds when the oxidation states of anions and cations are equal and have opposite signs. So one should be highly electronegative in nature and another should be highly electropositive in nature. So the electropositive element will be ready to give electrons and the electronegative element will be ready to accept all the electrons given by the electropositive element. As a whole the compound will be neutrally charged by adding of equal number of positively charged and negatively charged ions.

The reduction or addition of electrons will be occurring in cations and the oxidation or removal of electrons will be occurring in anions.

So the salt formation is based on neutralization reactions.

8 0
3 years ago
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