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4 years ago

In the equilibrium constant expression for the reaction below what is the correct exponent for N2O4?

1 answer:

7 0

As we have the balanced reaction equation is:

N2O4 (g) ↔ 2NO2(g)

from this balanced equation, we can get the equilibrium constant expression

KC = [NO2]^2[N2O4]^1

from this expression, we can see that [NO2 ] is with 2 exponent of the stoichiometric and we can see that from the balanced equation as NO2
is 2NO2 in the balanced equation.

and [N2O4] is with 1 exponent of the stoichiometric and we can see that from the balanced equation as N2O4 is 1 N2O4 in the balanced equation.

∴ the correct exponent for N2O4 in the equilibrium constant expression is 1

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Use the particle theory to explain,liquid to soild process

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The liquid to solid process using the particle theory is as below

The process that involve change of liquid to solid is known as Freezing
It involve change from a high energy state to lower energy

The constant temperature at which a liquid change to solid by giving out heat energy is called freezing point of the liquid
when liquid are cooled the thermal energy of particles decrease.
The cohesive forces between the particles strengthen to such extent that particles can have relative motion with each other and they occupy the fixed position, thus liquid is converted to solid

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3 years ago

Which of these reactions is an addition reaction?

Akimi4 [234]

Answer:

https://smartlyhelper.com/chemistry/question14062929

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3 years ago

3. 2.15 x 3.1 x 100 =

jeka94

Answer:

666.5

Explanation:

Multiply 2.15 and 3.1 to get 6.665.

6.665×100≈666.5

Multiply 6.665 and 100 to get 666.5.

666.5

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3 years ago

Read 2 more answers

A chemist prepares a solution of copper(II) sulfate CuSO4 by measuring out 31.μmol of copper(II) sulfate into a 150.mL volumetri

baherus [9]

Answer:

The concentration of the copper (II) sulfate solution is 2.06 * 10^2 μmol/L or 2.06 * 10^2 μM

Explanation:

The concentration of a solution is the amount of solute dissolved in a given volume of solution. In this case, the concentration of the copper(II) sulfate solution in micromoles per liter (symbol ) is the number of micromoles of copper(II) sulfate dissolved in each liter of solution. To calculate the micromoles of copper(II) sulfate dissolved in each liter of solution you must divide the total micromoles of solute by the number of liters of solution.

Here's that idea written as a formula: c= n/V

where c stands for concentration, n stands for the total micromoles of copper (II) sulfate and V stands for the total volume of the solution.

You're not given the volume of the solution in liters, but rather in milliliters. You can convert milliliters to liters with a unit ratio: V= 150. mL * 10^-3 L/ 1 mL = 0.150 L

Next, plug in μmol and liters into the formula to divide the total micromoles of solute by the number of liters of solution: c= 31 μmol/0.150 L = 206.66 μmol/L

Convert this number into scientific notation: 2.06 * 10^2 μmol/L or 2.06 * 10^2 μM

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2 years ago

Which two compounds are classified as bases by the Brønsted-Lowry definition, but not by the Arrhenius definition, and why?

konstantin123 [22]

Answer: Ammonia (NH3) and sodium carbonate (Na2CO3), because they accept hydrogen ions but lack hydroxide ions.

Explanation:

i took the test and got it correct :) hope this helps

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3 years ago