I need these questions answered

Chemistry

2 answers:

baherus [9]3 years ago

8 0

Answer:

Three objects with kinetic energy

A ball rolling down the street

Moving Car

Bullet

Law of Conservation of Energy states that the total energy of an isolated system remains constant; it is said to be conserved over time.

Though technically there are limitless forms of both types of energy, officially there's five types of kinetic energy: radiant, thermal, sound, electrical and mechanical and potential energy adds gravitational, nuclear, and elastic.

jenyasd209 [6]3 years ago

7 0

Because the there’s not enough inertia to keep the bouncy ball going at the same rate

You might be interested in

____ help scientists understand processes in the natural world by providing simpler representations of those processes.

Marina CMI [18]

Answer:

Models help scientists understand processes in the natural world by providing simpler representations of those processes.

7 0

3 years ago

I need help with this because it's easy for you guys but I don't understand it

WARRIOR [948]

Answer:

from nitrogen fixation in plants, lightning and bacteria

Explanation:

3 0

3 years ago

stoichometry in chemistry!! please someone help i'm begging you, if i fail this then i fail chemistry

Anna71 [15]

Answer:

You can find in the given attachemnet

4 0

2 years ago

If 5 mol of oxygen gas effuses through an opening in 10 seconds, how long will it take for the same amount of hydrogen gas to ef

andrezito [222]

Answer:

Explanation:

Recall the law of effusion:

$\displaystyle \frac{r_1}{r_2} = \sqrt{ \frac{\mathcal{M}_2}{\mathcal{M}_1} }$

Because 5 mol of oxygen was effused in 10 seconds, the rate is 0.5 mol/s.

Let the rate of oxygen be r₁ and the rate of hydrogen be r₂.

The molecular weight of oxygen gas is 32.00 g/mol and the molecular weight of hydrogen gas is 2.02 g/mol.

Substitute and solve for r₂:

$\displaystyle \begin{aligned} \frac{(0.5\text{ mol/s})}{r_2} & = \sqrt{\frac{(2.02\text{ g/mol})}{(32.00\text{ g/mol})}} \\ \\ r_2 & = \frac{0.5\text{ mol/s}}{\sqrt{\dfrac{(2.02\text{ g/mol})}{(32.00\text{ g/mol})}}} \\ \\ & = 2.0\text{ mol/s}\end{aligned}$