Answer:

Explanation:
The pressure at the bottom of the tank is:


The force exerted on the circular bottom is:
![F=(73581.921\,Pa)\cdot (\frac{\pi}{4} )\cdot [(12\,ft)\cdot (\frac{0.305\,m}{1\,ft} )]^{2}](https://tex.z-dn.net/?f=F%3D%2873581.921%5C%2CPa%29%5Ccdot%20%28%5Cfrac%7B%5Cpi%7D%7B4%7D%20%29%5Ccdot%20%5B%2812%5C%2Cft%29%5Ccdot%20%28%5Cfrac%7B0.305%5C%2Cm%7D%7B1%5C%2Cft%7D%20%29%5D%5E%7B2%7D)

Answer:
3.8 M
Explanation:
Volume of acid used VA= 57.0 - 37.5 = 19.5 ml
Volume of base used VB= 67.8 - 45.0 = 22.8 ml
Equation of the reaction
2HNO3(aq) + Ca(OH)2(aq) --------> Ca(NO3)2(aq) + 2H2O(l)
Number of moles of acid NA= 2
Number of moles of base NB= 1
Concentration of acid CA= ???
Concentration of base CB= 1.63 M
CAVA/CBVB = NA/NB
CAVANB = CBVBNA
CA= CBVBNA/VANB
CA= 1.63 × 22.8 × 2/ 19.5 × 1
CA= 3.8 M
HENCE THE MOLARITY OF THE ACID IS 3.8 M.
Answer:F
During translation, mRNA is held in the
large ribosomal subunit.
Explanation: UwU SRRY For no real answer
I believe its false because chlorophyll absorbs light from the sun, it doesn't reflect it.
This is an incomplete question, here is a complete question.
Consider the second-order decomposition of nitroysl chloride:

At 450 K the rate constant is 15.4 atm⁻¹s⁻¹. How much time (in s) is needed for NOCl originally at a partial pressure of 53 torr to decay to 10.6 torr?
Answer : The time needed for NOCl is, 2.52 seconds.
Explanation : Given,
Rate constant = 
Initial partial pressure of NOCl = 56 torr = 0.0737 atm
final partial pressure of NOCl = 14.5 torr = 0.0191 atm
The expression used for second order kinetics is:
![kt=\frac{1}{[A_t]}-\frac{1}{[A_o]}](https://tex.z-dn.net/?f=kt%3D%5Cfrac%7B1%7D%7B%5BA_t%5D%7D-%5Cfrac%7B1%7D%7B%5BA_o%5D%7D)
where,
k = rate constant
t = time
= concentration at time 't'
= initial concentration
As we know that,

Thus, the expression of second order kinetics will be:


As, 
So,
............(1)
Now put all the given values in the above expression 1, we get:


Therefore, the time needed for NOCl is, 2.52 seconds.