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vladimir1956 [14]
3 years ago
9

Please answer the question circled in red

Chemistry
2 answers:
ki77a [65]3 years ago
5 0

Answer:

i need more info bro

Explanation:

Tresset [83]3 years ago
5 0
I need more information in order to help you solve the question bro.. lol otherwise I can’t be of much help.
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An object has a volume of 2 milliliters and a mass of 10 grams, calculate the density of the object
MArishka [77]
5000 kilogram/cubic meter
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3 years ago
A PNP transistor is connected in a circuit so that the collector-base junction remains reverse biased and the emitter-base junct
maw [93]
Here are the choices:

A. the output current will be much smaller than the input current. 
<span>B. the output voltage will be much larger than the input voltage. </span>
<span>C. the output voltage will be much smaller than the input voltage. </span>
<span>D. the output current will be much larger than the input current
</span>
The correct answer is letter <span>B. the output voltage will be much larger than the input voltage.</span>
5 0
3 years ago
according to the third law if a football player hits another player with an action force of 1500n how much will the reaction for
djyliett [7]

Answer:

The reaction would be 1500n (equal reaction)

Explanation:

This can be explained by Newton's third law of motion which states that for every action (force), there is an opposite and equal reaction. In other words, when two objects or people come in contact, the magnitude of force which they exert on each other is equal and they both feel an equal reaction force.

It doesn't matter whether one of the colliding bodies is of bigger mass than the other.  This Newton's third law of motion is also known as the law of action and reaction.

3 0
3 years ago
Molar mass of 4Fe(OH)2
lakkis [162]

Answer: The molar mass and molecular weight of 4Fe is 223.38.

3 0
2 years ago
A solution is made by adding 35.5 mL of concentrated hydrochloric acid ( 37.3 wt% , density 1.19 g/mL1.19 g/mL ) to some water i
erastova [34]

Answer:

1.73 M

Explanation:

We must first obtain the concentration of the concentrated acid from the formula;

Co= 10pd/M

Where

Co= concentration of concentrated acid = (the unknown)

p= percentage concentration of concentrated acid= 37.3%

d= density of concentrated acid = 1.19 g/ml

M= Molar mass of the anhydrous acid

Molar mass of anhydrous HCl= 1 +35.5= 36.5 gmol-1

Substituting values;

Co= 10 × 37.3 × 1.19/36.5

Co= 443.87/36.6

Co= 12.16 M

We can now use the dilution formula

CoVo= CdVd

Where;

Co= concentration of concentrated acid= 12.16 M

Vo= volume of concentrated acid = 35.5 ml

Cd= concentration of dilute acid =(the unknown)

Vd= volume of dilute acid = 250ml

Substituting values and making Cd the subject of the formula;

Cd= CoVo/Vd

Cd= 12.16 × 35.5/250

Cd= 1.73 M

7 0
3 years ago
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