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valkas [14]
3 years ago
6

If Pam can install 12 insulators in 15 hours, how long does it take to install one insulator

Mathematics
2 answers:
Xelga [282]3 years ago
7 0
The time it takes to install 1 insulator would be 1.25 hours
zhenek [66]3 years ago
7 0
Hi , the answer is 4 hours because 12insulators-15hours 11-14hours 10-13hours 9-12hours 8-11hours 7-10hours 6-9hours 5-8hours 4-7hours 3-6hours 2-5hours 1-4hours
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carli bought a new pair of jean for $60 if the tax if the tax rate is 8.25% how much will carli have to pay for the jeans includ
Sever21 [200]

Answer:

2.5075

Step-by-step explanation:

If the sales tax rate is 7.375% in New York State then how much sales tax would you pay in Albany for a $34 pair of pants

Sales Tax. If the sales tax rate is 7.375% in New York State, then how much sales tax would you pay in Albany for a $34 pair of pants? 34.00 x 0.07375 = 2.5075.

4 0
3 years ago
3. In triangle ABC, m&lt;BAC = 4x + 10, m&lt;ABC = 5x + 18, and m&lt;BCA = 3x - 16. <br>(a) Find the value of x. <br>(b) Find th
belka [17]

(a) Find the value of x.

Sum of interior in a triangle = 180

So m<BAC  + m<ABC + m<BCA = 180

4x + 10 + 5x + 18 + 3x - 16 = 180

12x + 12 = 180

12x = 168

  x = 14


(b) Find the measure of <3.

<3 + <BCA = 180

<BCA = 3x - 16 = 3(14) - 16 = 26°

So

<3 = 180 - <BCA

<3 = 180 - 26

<3 = 154°

7 0
3 years ago
Whats The square root of 69?
Ber [7]

Square root of 69= 8.306624


check the answer

8.3^2= 8.3*8.3= 68.89

now round 68.89 = 69


I hope that's help!

6 0
3 years ago
Read 2 more answers
Find the exact value of cos(sin^-1(-5/13))
son4ous [18]

bearing in mind that the hypotenuse is never negative, since it's just a distance unit, so if an angle has a sine ratio of -(5/13) the negative must be the numerator, namely -5/13.

\bf cos\left[ sin^{-1}\left( -\cfrac{5}{13} \right) \right] \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{then we can say that}~\hfill }{sin^{-1}\left( -\cfrac{5}{13} \right)\implies \theta }\qquad \qquad \stackrel{\textit{therefore then}~\hfill }{sin(\theta )=\cfrac{\stackrel{opposite}{-5}}{\stackrel{hypotenuse}{13}}}\impliedby \textit{let's find the \underline{adjacent}}

\bf \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{13^2-(-5)^2}=a\implies \pm\sqrt{144}=a\implies \pm 12=a \\\\[-0.35em] ~\dotfill\\\\ cos\left[ sin^{-1}\left( -\cfrac{5}{13} \right) \right]\implies cos(\theta )=\cfrac{\stackrel{adjacent}{\pm 12}}{13}

le's bear in mind that the sine is negative on both the III and IV Quadrants, so both angles are feasible for this sine and therefore, for the III Quadrant we'd have a negative cosine, and for the IV Quadrant we'd have a positive cosine.

8 0
3 years ago
heres the triangle sorry i couldn’t add it threw the comments
Dmitry [639]

Answer:

Step-by-step explanation:

Are we suppose to solve for something or what there are no instructions

3 0
3 years ago
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