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Luba_88 [7]
3 years ago
15

1. Trace the pathway of electrons from glucose through aerobic cellular respiration (all parts) and describe all important event

s where energy is transferred from one molecule to another.
Physics
1 answer:
kicyunya [14]3 years ago
4 0

Answer:

Explanation:

(1). REDUCTION-OXIDATION REACTION:

Energy is derived from electrons in glucose or glucose metabolites.

(2). MAIN REACTION:

Which is the reaction below;

NAD^+1 + 2 NADH + H^+)

In the equation above Glycolysis provides electrons through 2 NADH which is The hormone insulin signals to the cell's plasma membrane to transport, glucose into the cell, Glycolysis means the breakdown of the glucose molecule.The process breaks glucose down into 2 molecules of Pyruvate, Pyruvate is the ionized form of pyruvic acid, Each molecule of pyruvate contains 3 carbons.

(3). KREBS : provision of electrons through 6 NADH and 2 FADH2. The main aim here is to use the pyruvates to produce more ATP. Oxygen plays an important role here.

Water is the by- product.

Electrons power the proteins and the remaining energy from the glucose is released by the electron transport chain.

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Explanation:

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3 years ago
a resistor, of resistance 47 , is damaged when it dissipates a power greater than 0.5W. determine the maximum voltage that can b
harkovskaia [24]

Answer:

<em>The maximum voltage that can be applied without damaging the resistor is 4.85 V</em>

Explanation:

<u>Electric Power in a Resistor</u>

Given a resistor or resistance R connected to a circuit of voltage V carrying a current I. The relation between these three magnitudes is given by Ohm's Law:

V = R.I

The dissipated power P of a resistor can be calculated by the following equation, known as Joule's first law:

P = I^2.R

Solving the first equation for I:

\displaystyle I=\frac{V}{R}

Substituting in the second equation:

\displaystyle P=\frac{V^2}{R^2}.R

Simplifying:

\displaystyle P=\frac{V^2}{R}

Solving for V:

V=\sqrt{P.R}

The resistor has a resistance of R=47Ω and can hold a maximum power of P=0.5 W, thus the maximum voltage is:

V=\sqrt{0.5\cdot 47}

V=\sqrt{23.5}

V = 4.85 V

The maximum voltage that can be applied without damaging the resistor is 4.85 V

6 0
3 years ago
Suppose 310. grams of ethanol (ethyl alcohol) is in an aluminum cup of 90.0 grams. Both of these are at 30.0C. A mass m of ice a
Ira Lisetskai [31]

Answer:

Explanation:

Given

mass of ethanol m_e=310\ gm

mass of aluminium cup m_{al}=90\ gm

both are at an initial temperature of T_i=30^{\circ}C

specific heat of ethanol c_e=2.46\ J/g-K

specific heat of aluminium c_{al}=0.9\ J/g-K

specific heat of ice c_i=2.108\ J/g-K

specific heat of water c_w=4.184\ J/g-K

Latent heat of fusion L=334\ J/gm

suppose m is the mass of ice added

Heat loss by Al cup and ethanol after 18^{\circ}C is reached

Q_1=(310\times 2.46+90\times 0.9)\cdot (30-18)

Heat gained by ice such that ice is melted and reached a temperature of 18^{\circ}C

Q_2=m\times 2.108\times (8.5)+m\times 334

Comparing 1 and 2 we get

m=23.65\ gm

Thus 23.65 gm of ice is added

                 

8 0
3 years ago
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Answer:

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3 0
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