Estimate the optimal number of neutrons for a nucleus containing 70 protons.
2 answers:
The optimal number of neutrons for a nucleus containing 70 protons is 130
<h3>Further explanation </h3>In chemistry, the nucleus is the positively charged center of the atom that consist of protons and neutrons. It's also known as the "atomic nucleus"
The neutron is a subatomic particle with no net electric charge and a mass slightly greater than that of a proton. The neutron is have symbol n or n⁰. Protons and neutrons constitute the nuclei of atoms.
Neutron is a type of atomic particle which does not possess any kind of charge on it. It has neutral behavior toward atoms since it does not possess any kind of charges but it contributes to the mass of the atoms.
Atomic number = 70
Atomic weight = 173
Atomic weight = number of protons + number of neutrons
Atomic number = number of protons
Therefore, the number of protons = 70
Number of neutrons = atomic weight - number of protons
Number of neutrons = 173 - 70 = 103
Optimal number of neutrons = 130
<h3>Learn more</h3>- Learn more about neutrons brainly.com/question/1823582
- Learn more about nucleus brainly.com/question/2345919
- Learn more about protons brainly.com/question/2166462
<h3>Answer details</h3>
Grade: 9
Subject: chemistry
Chapter: the optimal number of neutrons
Keywords: protons, nucleus, neutrons
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Answer:
A. fluorine, 1.79 moles
Explanation:
Given parameters:
Mass of carbon = 87.7g
Mass of fluorine gas = 136g
Unknown:
The limiting reactant and the maximum amount of moles of carbon tetrafluoride that can be produced = ?
Solution:
Equation of the reaction:
C + 2F₂ → CF₄
let us find the number of the moles the given species;
Number of moles =
C; molar mass = 12;
Number of moles = = 7.31moles
F; molar mass = 2(19) = 38g/mol
Number of moles = = 3.58moles
So;
From the give reaction:
1 mole of C requires 2 moles of F₂
7.31 moles of C will then require 2 x 7.31 moles of F₂ = 14.62moles
But we have 3.58 moles of the F₂;
Therefore, the reactant in short supply is F₂ and it is the limiting reactant;
So;
2 moles of F₂ will produce mole of CF₄
3.58 moles of F₂ will then produce = 1.79moles of CF₄