Yield is the measured amount of a product obtained from a reaction.
Hope that's helpful
In order to solve this, we need to know the standard cell potentials of the half reaction from the given overall reaction.
The half reactions with their standard cell potentials are:
<span>2ClO−3(aq) + 12H+(aq) + 10e- = Cl2(g) + 6H2O(l)
</span><span>E = +1.47
</span>
<span>Br(l) + 2e- = 2Br-
</span><span>E = +1.065
</span>
We solve for the standard emf by subtracting the standard emf of the oxidation from the reducation, so:
1.47 - 1.065 = 0.405 V
Hydrogen maybe but I don’t know for sure
<u>Answer:</u> The fugacity coefficient of a gaseous species is 1.25
<u>Explanation:</u>
Fugacity coefficient is defined as the ratio of fugacity and the partial pressure of the gas. It is expressed as ![\bar{\phi}](https://tex.z-dn.net/?f=%5Cbar%7B%5Cphi%7D)
Mathematically,
![\bar{\phi}_i=\frac{\bar{f_i}}{p_i}](https://tex.z-dn.net/?f=%5Cbar%7B%5Cphi%7D_i%3D%5Cfrac%7B%5Cbar%7Bf_i%7D%7D%7Bp_i%7D)
Partial pressure of the gas is expressed as:
![p_i=\chi_iP](https://tex.z-dn.net/?f=p_i%3D%5Cchi_iP)
Putting this expression is above equation, we get:
![\bar{\phi}_i=\frac{\bar{f_i}}{\chi_iP}](https://tex.z-dn.net/?f=%5Cbar%7B%5Cphi%7D_i%3D%5Cfrac%7B%5Cbar%7Bf_i%7D%7D%7B%5Cchi_iP%7D)
where,
= fugacity coefficient of the gas
= fugacity of the gas = 25 psia
= mole fraction of the gas = 0.4
P = total pressure = 50 psia
Putting values in above equation, we get:
![\bar{\phi}_i=\frac{25}{0.4\times 50}\\\\\bar{\phi}_i=1.25](https://tex.z-dn.net/?f=%5Cbar%7B%5Cphi%7D_i%3D%5Cfrac%7B25%7D%7B0.4%5Ctimes%2050%7D%5C%5C%5C%5C%5Cbar%7B%5Cphi%7D_i%3D1.25)
Hence, the fugacity coefficient of a gaseous species is 1.25
It's A. volume
Pressure =
![\frac{moles * const * temperature}{volume}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bmoles%20%2A%20const%20%2A%20temperature%7D%7Bvolume%7D%20)
with const depends on the chosen unit of volume
I think so...