How many grams of hcl are produced when 10.0 g of cl2 and 1.00 g of h2 react? h2(g) cl2(g) ---> 2 hcl(g)?
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Answer:
Average rate of reaction expressed in moles H₂ consumed per liter per second = 0.0025 M/s = 0.0025 mol/L.s
Explanation:
The complete, correct Question, is presented in the attached image to this answer.
The average rate of reaction in terms of the reactant is defined as the total amount of reactant consumed over a period of time divided by total period of time.
Mathematically,
Average rate of reaction = (change in concentration of H₂ over a period of time) ÷ (total period of time)
Average rate of reaction = (-ΔC)/(Δt)
The minus sign is there because the concentration of reactants reduce with time.
change in concentration of H₂ = -ΔC
= -(0.02 - 0.03) = 0.01 M
Time = Δt = 4 - 0 = 4.0 s
Average rate of reaction = (0.01/4) = 0.0025 M/s
We could solve for the average rate of reaction expressed in moles Cl₂ consumed per liter per second
change in concentration of Cl₂ = -ΔC
= -(0.04 - 0.05) = 0.01 M
Time = Δt = 4 - 0 = 4.0 s
Average rate of reaction = (0.01/4) = 0.0025 M/s = 0.0025 mol/L.s
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