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dlinn [17]
3 years ago
6

How many grams of hcl are produced when 10.0 g of cl2 and 1.00 g of h2 react? h2(g) cl2(g) ---> 2 hcl(g)?

Chemistry
1 answer:
zmey [24]3 years ago
8 0
I belive all you have to do is add cl making 20g then u must also add2.00 because the reactant is 2HCl because the 2 is out front that makes both elements take them equaling 22.00
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Answer:

\huge \underline\bold\red{Answer}

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Answer:

Option (B) 7

Explanation:

C3H6O2(l) + O2(g) → CO2(g) + H2O(l)

To know the coefficient of O2 in the above equation, let us balance the equation.

The above equation can be balance as follow:

C3H6O2(l) + O2(g) → CO2(g) + H2O(l)

There are 3 atoms of C on the left side and 1 atom on the right side. It can be balance by putting 3 in front of CO2 as shown below:

C3H6O2(l) + O2(g) → 3CO2(g) + H2O(l)

There are 6 atoms of H on the left side and 2 atoms on the right side. It can be balance by putting 3 in front of H2O as shown below:

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There are a total of 4 atoms of O on the left side and a total of 9 atoms on the right side. It can be balance by putting 7/2 in front of O2 as show below:

C3H6O2(l) + 7/2O2(g) → 3CO2(g) + 3H2O(l)

Multiply through by 2

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Now, the equation is balanced.

From the balanced equation above, the coefficient of O2 is 7.

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zhannawk [14.2K]

Answer: im thinking its gonna be d.C2H6 and also

the explanation is on the research i had did before i had answered this question so i really hope this help :)

Explanation:

Ar = van de waals forces or london forces

C

H

4

= van de waals forces or london forces

HCl=permanent dipole-dipole interactions

CO = permanent dipole-dipole interactions

HF = hydrogen bonding

N

a

N

O

3

= permanent dipole-dipole interactions

C

a

C

l

2

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