<span>You are given two cars, one in front of the other, that are traveling down the highway at 25 m/s. You are also given a frequency of 500 Hz of the car travelling behind it. You are asked what is the frequency heard by the driver of the lead car. This problem can be solved using the Doppler effect
sound frequency heard by the lead car = [(speed of sound + lead car velocity)/( speed of sound + behind car velocity)] * (sound of frequency of the behind car)
</span>sound frequency heard by the lead car = [(340 m/s + 25 m/s)/(340 m/s - 25 m/s)] * (500 Hz)
sound frequency heard by the lead car = 579 Hz
Answer:
he tension in an elevator cable is 10,000 N. The elevator itself has a mass of 500 kg.
Explanation:
<u>Answer:</u>
The velocity of the truck is 34 m/s.
<u>Explanation:</u>
The momentum (p) of an object is the product of its mass (m) and its velocity (v) which can be written as:
<em>p = mv</em>
Here in this problem, we are given a truck which has a momentum of 40120 kg and a mass of 1180 kg and we are to find its velocity.
So substituting the given values in the above formula to find the velocity of the truck.
Truck's velocity =
= 34 m/s.
Refer to the diagram shown below.
W = 87.5 N, the weight of the sandwiched board.
μ = 0.622, the static coefficient of friction.
From the free body diagram of the sandwiched board, obtain
2μF = W
F = W/(2μ) = 87.5/(2*0.622) = 70.34 N
Answer: 70.34 N
I think this is shown in the fine print on the second sheet . . .
The question starts out by saying that the scale uses <u>two</u> 3V cells <u>in series</u>.
That makes the total battery voltage 6 volts.
0.12 milliamperes = 0.00012 Amperes.
Resistance = (voltage) / (current in Amperes).
Resistance = 6 / 0.00012 = 50,000 Ω