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Reptile [31]
3 years ago
14

What forms when acid reacts with a base? please help

Physics
1 answer:
BARSIC [14]3 years ago
7 0

Answer:

salt. (I think)

Explanation:

they neutralize each other and often this results in salt being formed and leftover

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The acceleration of gravity is a constant equal to _______ meters per second squared.
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B. 9.8.
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AYUDA :( Calcular el trabajo desarrollado por la fuerza de fricción, si la fuerza "F" desplaza al bloque de una distancia de 40m
kogti [31]

Answer:

sorry can you translate

Explanation:

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A ball at rest rolls across a frictionless floor at 12.0 m/s/s. How far will it travel in
professor190 [17]

Answer:

The distance, d travelled by the ball is 768 metres.

Explanation:

In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.

This simply means that, acceleration is given by the subtraction of final speed from the initial speed all over time.

Hence, if we subtract the final speed from the initial speed and divide that by the time, we can calculate an object’s acceleration.

Mathematically, acceleration is given by the equation;

Acceleration (a) = \frac{initial \; speed  -  final \; speed}{time}

a = \frac{v  -  u}{t}

Where,

a is acceleration measured in ms^{-2}

v and u is initial and final speed respectively, measured in ms^{-1}

t is time measured in seconds.

Given the following data;

Acceleration = 12.0m/s²

Time, t = 8secs

Velocity =?

First, we would calculate its velocity;

a = \frac{v  -  u}{t}

Since the ball rolls at rest, initial velocity is zero (0).

V = a * t

V = 12 * 8

Velocity = 96ms^{-1}

We can now solve for the distance;

Velocity = \frac{distance}{time}

Therefore,

Distance = velocity * time

Distance = 96 * 8

Distance = 768m.

3 0
3 years ago
A student slides her 80.0-kg desk across the level floor of her dormitory room a distance 4.00 m at constant speed. If the coeff
zysi [14]

Answer:

Work done is equal to 125.44 J

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We have given mass of the student m = 80 kg

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Acceleration due to gravity g=9.8m/sec^2

Coefficient of kinetic friction \mu =0.4

So normal force exerted by student F=\mu mg=0.4\times 80\times 9.8=313.6N

We know that work done is equal to multiplication of force and distance

So work done W=Fd=313.6\times 0.4=125.44J

7 0
3 years ago
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