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wolverine [178]
4 years ago
10

How is mercury obtained and separated from other nearby substances?

Physics
1 answer:
wolverine [178]4 years ago
8 0
Mercury forms in an ore called cinnabar, it is also frequently found in small amounts in other ores.

A method for separating mercury from cinnabar is to crush the ore and then heat it in a furnace in order to vaporize the mercury.
You might be interested in
As you climb a mountain, you can expect the air temperature to decrease by 6.5 degrees C for every 1000 meters you ascend. This
Reptile [31]

Answer:

the answer will be C.  4 degrees C

Explanation:

you subtract base meters from peak meters to get 4 meters; then Multiply 6.5 by 4.

Then subtract that total from 30 degrees C

***as altitude increases, temperature decreases***

6 0
3 years ago
Write a scientific question that is specific and testable. Jack and Jill when up a hill to fetch a pail of water. Once they got
Naya [18.7K]

The scientific method consists of making an observation, ask a question, formulate hypothesis, predict, test, iterate

The scientific question that can be asked is; <u>What is the </u><u>depth of the well</u>

<u />

The reason why the above question is appropriate is as follows:

The items Jack and Jill found at the well

  • No pail
  • A stopwatch
  • Nine equal sized rocks

The information they can get using what they found are;

The time it takes the rock to reach the water surface in the well

The depth of the well

The well's depth, <em>h</em>, is given using the equation of free fall, as follows;

h = \dfrac{1}{2} \cdot g \cdot t^2

Where;

g ≈ Acceleration due to gravity ≈ 9.81 m/s²

By recording the time each rock takes to reach the water surface in the well, the average depth of the well, h_{ave}, can be found by finding the average of the 9 calculated values for <em>h</em> using the 9 stones

Therefore;

The scientific question that is specific and testable is <u>how </u><u>deep </u><u>is the </u><u>well</u><u>, or what is the well's depth</u>

Learn more about scientific method here:

brainly.com/question/13096299

3 0
3 years ago
HELP I DON'T PAY ATTENTION ENOUGH
Setler [38]

Answer:

I think 1 is d and 2 is A

Explanation:

but I may be wrong and I am so sorry if I am

8 0
3 years ago
Read 2 more answers
A 4.0×1010kg asteroid is heading directly toward the center of the earth at a steady 16 km/s. To save the planet, astronauts str
blondinia [14]

Answer:

a. t = 69.4 hr = 2.89 days

b. theta = 91.67*10^-3 degrees

c.  deflection_angle = 0.134 degrees

Explanation:

a).

The asteroid impacts the earth in t

t = x/v = (4.0*10^6 km)/(16 km/sec)

t = 2.5 * 10^5 sec

t = 69.4 hr = 2.89 days

b).

tan(theta) = 6400 km/(4.0*10^6 km)

tan(theta) = 1.6*10^-3

theta = arctan(1.6*10^-3)

theta = 1.6*10^-3 radians  (for small angles, tan(theta) ~= theta)

theta = 91.67*10^-3 degrees

c).

v_minimum = 6400 km/(2.5 * 10^5 sec)

v_minimum = 25.6 m/s

Using F = m*a, we can calculate the acceleration of the asteroid due to the rocket's thrust:

5.0*10^9 N = 4.0*10^10 kg * a

a = (5.0*10^9 N)/(4.0*10^10 kg)  

a = 0.125 m/s^2

The transverse velocity after 300 seconds of this acceleration is:

v_transverse = a*t = 0.125 m/s^2 * 300 s

v_transverse = 37.5 m/s = 37.5*10^-3 km/s

tan(deflection_angle) = v_transverse/(20 km/s)

tan(deflection_angle) = (37.5*10^-3 km/s)/(16 km/s) = 2.34^-3

deflection_angle = arctan(2.34*10^-3)  

deflection_angle = 2.34*10^-3 radians = 0.134 degrees

v_transverse/(16 km/s) > (6400km)/(5.0*10^6 km)  

(note that the right hand side if this inequality is tan(theta) calculated above)

v_transverse > 23.704 m/

8 0
3 years ago
Walking dancing and even some household chores are? ​
kramer

Answer:

Actions

Explanation:

if u mean what are these called then it's actions

3 0
3 years ago
Read 2 more answers
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