So Hooke's law says that that law is proportional to how much I stretch the spring. Alright. So f=kx<span>. x is the length of the spring now minus its length when it's relaxed and nobody's pulling on it. k is a constant called the spring constant.</span>
Answer:
Angular momentum is conserved if there are no external forces
P1 = P2
I1 ω1 = I2 ω2
ω2 / ω1 = I1 / I2
If the skater pulls their arms in (I2 < I1) then the angular speed must increase for angular momentum to be conserved.
Given:
v(final velocity)= 7.5 m/s
t(time taken to pedal along)=4.5 s
Displacement (s)=19 m
Now we know that
s=ut+1/2(at^2)
Where s is the displacement measured in m
u is the initial velocity measured in m/sec
a is the acceleration measured in m/s^2.
t is the time taken to cover this distance.
Substituting the given values in the above formula we get
19= 4.5u+1/2(a x 4.5 x 4.5)
20.25 a + 9 u = 38
Now we also know that
v= u + at
Substituting the given values in the above formula we get
7.5= u + 4.5a
Solving for u and a from the above equations we get
u = 0.944m/s
a= 1.45 m/s^2
Thus the initial velocity is 0.944 m/s
Answer:
2.4564 m/s
Explanation:
Number of waves in 1 second
This is the frequency 0.267 Hz
The distance mentioned in the question is the
= Wavelength = 9.2 m
The speed of wave is
The speed of the wave is 2.4564 m/s
I hope this helps you out!