The distance from the Earth's center to the point outside the Earth is 55800 Km
<h3>How to determine the distance from the surface of the Earth</h3>
- Acceleration due to gravity of Earth = 9.8 m/s²
- Acceleration due to gravity of the poin (g) = 1/60 × 9.8 = 0.163 m/s²
- Gravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²
- Mass of the Earth (M) = 5.97×10²⁴ Kg
- Distance from the surface of the Earth (r) =?
g = GM / r²
Cross multiply
GM = gr²
Divide both sides by g
r² = GM / g
Take the square root of both sides
r = √(GM / g)
r = √[(6.67×10¯¹¹ × 5.97×10²⁴) / 0.163)]
r = 4.94×10⁷ m
Divide by 1000 to express in Km
r = 4.94×10⁷ / 1000
r = 4.94×10⁴ Km
<h3>How to determine the distance from the center of the Earth</h3>
- Distance from the surface of the Earth (r) = 4.94×10⁴ Km
- Radius of the Earth (R) = 6400 Km
- Distance from the centre of the Earth =?
Distance from the centre of the Earth = R + r
Distance from the centre of the Earth = 6400 + 4.94×10⁴
Distance from the centre of the Earth = 55800 Km
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To solve this problem it is necessary to apply the concepts related to the continuity of fluids in a pipeline and apply Bernoulli's balance on the given speeds.
Our values are given as


From the continuity equations in pipes we have to

Where,
= Cross sectional Area at each section
= Flow Velocity at each section
Then replacing we have,



From Bernoulli equation we have that the change in the pressure is

![7.3*10^3 = \frac{1}{2} (1000)([ \frac{(1.25*10^{-2})^2 }{0.6*10^{-2})^2} v_1 ]^2-v_1^2)](https://tex.z-dn.net/?f=7.3%2A10%5E3%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%281000%29%28%5B%20%5Cfrac%7B%281.25%2A10%5E%7B-2%7D%29%5E2%20%7D%7B0.6%2A10%5E%7B-2%7D%29%5E2%7D%20v_1%20%5D%5E2-v_1%5E2%29)


Therefore the speed of flow in the first tube is 0.9m/s
Answer:
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Explanation:
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Time/sec. the x-axis is always the independent variable.