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3 years ago

What do the space between contour lines represent?

1 answer:

4 0

Closely spaced contour lines represent steep slopes, conversely, contour lines that are spaced far apart represent gentle slopes. Contour lines trend up valleys and form a "V" or a "U" where they cross a stream.

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What is the best thing to study in Antartica?

Dvinal [7]

The animals, climate, weather.

5 0

3 years ago

Read 2 more answers

A solution was made by mixing 60.5 g of glucose (C6H12O6) with enough water to make 325 ml of solution. What is the percent (mas

IgorC [24]

mass percent concentration = 15.7 %

molar concentration of glucose solution 1.03 M

Explanation:

To calculate the mass percent concentration of the solution we use the following formula:

concentration = (solute mass / solution mass) × 100

solute mass = 60.5 g

solution mass = solute mass + water mass

solution mass = 60.5 + 325 = 385.5 g (I used the assumption that the solution have a density of 1 g/mL)

concentration = (60.5 / 385.5) × 100 = 15.7 %

Now to calculate the molar concentration (molarity) of the solution we use the following formula:

molar concentration = number of moles / volume (L)

number of moles = mass / molecular weight

number of moles of glucose = 60.5 / 180 = 0.336 moles

molar concentration of glucose solution = 0.336 / 0.325 = 1.03 M

Learn more about:

molarity

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5 0

4 years ago

Current passes through a solution of sodium chloride. In 1.00 second, 2.68×1016Na+ ions arrive at the negative electrode and 3.9

EleoNora [17]

Answer : The current passing between the electrodes is, $1.056\times 10^{-2}A$

Explanation :

First we have to calculate the charge of sodium ion.

$q=ne$

where,

q = charge of sodium ion

n = number of sodium ion = $2.68\times 10^{16}$

e = charge on electron = $1.6\times 10^{-19}C$

Now put all the given values in the above formula, we get:

$q=(2.68\times 10^{16})\times (1.6\times 10^{-19}C)=4.288\times 10^{-3}C$

Now we have to calculate the charge of chlorine ion.

$q'=ne$

where,

q' = charge of chlorine ion

n = number of chlorine ion = $3.92\times 10^{16}$

e = charge on electron = $1.6\times 10^{-19}C$

Now put all the given values in the above formula, we get:

$q'=(3.92\times 10^{16})\times (1.6\times 10^{-19}C)=6.272\times 10^{-3}C$

Now we have to calculate the current passing between the electrodes.

$I=\frac{q}{t}+\frac{q'}{t}$

$I=\frac{4.288\times 10^{-3}}{1.00}+\frac{6.272\times 10^{-3}}{1.00}$

$I=1.056\times 10^{-2}A$

Thus, the current passing between the electrodes is, $1.056\times 10^{-2}A$

4 0

3 years ago

Diborane (B2H6) has been considered as a possible rocket fuel. Calculate DH° for the reaction B2H6(g) ---> 2B(s) + 3H2(g) usi

svlad2 [7]

Answer:

A. DH° = –36 kJ

Explanation:

It is possible to obtain DH° of a reaction by the sum of DH° of half reactions. The DH° of the reaction:

B₂H₆(g) → 2B(s) + 3H₂(g)

Could be obtained from:

<em>(1) </em>2B(s) + 1.5O₂(g) → B₂O₃(s) DH° = –1273kJ

<em>(2) </em>B₂H₆(g) + 3O₂(g) → B₂O₃(s) + 3H₂O(g) DH° = –2035kJ

<em>(3) </em>H₂(g) + 0.5O₂(g) → H₂O(g) DH° = –242kJ

The sum of (2) - (1) gives:

B₂H₆(g) + 1.5O₂(g) → 2B(s) + 3H₂O(g) DH° = -2035kJ - (-1273kJ) = -762kJ

Now, this reaction - 3×(3):

B₂H₆(g) → 2B(s) + 3H₂(g) DH° = -762kJ - (3×-242kJ) = -36kJ

Thus, right answer is:

3 0

4 years ago

A que temperatura se produce el punto de fusión

Sholpan [36]

Answer:

Explanation:

At what temperature does the melting point occur?

32°F /0°C

(32°F − 32) × 5/9 = 0°C

At temperatures above 32°F (0°C), pure water ice melts and changes state from a solid to a liquid (water); 32°F (0°C) is the melting point. For most substances, the melting and freezing points are about the same temperature.

Is Melting Point affected by temperature?

Melting point, the temperature at which the solid and liquid forms of a pure substance can exist in equilibrium. As heat is applied to a solid, its temperature will increase until the melting point is reached. More heat then will convert the solid into a liquid with no temperature change.

6 0

3 years ago