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stira [4]
3 years ago
9

What is 4.07 cm x 2.3cm, rounded to the correct number of significant figures

Chemistry
1 answer:
Tom [10]3 years ago
8 0

Answer: 9.4cm^2

Explanation:

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I NEED HELP PLEASE ASAP! BRAINLIEST :)
Keith_Richards [23]

Answer:

6. d

7.c

8.a

9.b

Explanation:

For 6, the answers are not particularly close to 100, and they are not clustered much. For 7, the answers are all clustered very close to 100. For 8, the answers are clustered closely, but not close to 100. For 9, the answers are close to 100, but not clustered very tightly. Hope this helps!

6 0
2 years ago
When solving a problem it is important to identify your given and needed units, but it is also important to understand the relat
Angelina_Jolie [31]

Answer:

The question has some details missing. here are the details ; Given the following ;  

1. 43.2 g of tablet with 20 cm3 of space

2. 5 cm3 of tablets weighs 10.8 g

3. 5 g of balsa wood with density 0.16 g/cm3

4. 150 g of iron. With density 79g/cm 3

5. 32 cm3 sample of gold with density 19.3 g/cm3

6. 18 ml of cooking oil with density 0.92 g/ml

Explanation:

<u>Appropriate for calculating mass</u>

32 cm3 sample of gold with density 19.3 g/cm3

18 ml of cooking oil with density 0.92 g/ml

<u>Appropriate for calculating volume</u>

5 g of balsa wood with density 0.16 g/cm3

150 g of iron. With density 79g/cm 3

<u>Appropriate for calculating density</u>

43.2 g of tablet with 20 cm3 of space

5 cm3 of tablets weighs 10.8 g

3 0
3 years ago
How to calculate the number of moles
babunello [35]

Answer:

1. The formula for the number of moles formula is expressed as.

2. Given.

3. Number of moles formula is.

4. Number of moles = Mass of substance / Mass of one mole.

5. Number of moles = 95 / 86.94.

6 0
3 years ago
Metamorphic rocks are formed by
marin [14]

Answer:

Heat and pressure.

Explanation:

Hope this helps!

7 0
3 years ago
The two isotopes of chlorine are LaTeX: \begin{matrix}35\\17\end{matrix}Cl35 17 C l and LaTeX: \begin{matrix}37\\17\end{matrix}C
Kay [80]

<u>Answer:</u> The percentage abundance of _{17}^{35}\textrm{Cl} and _{17}^{37}\textrm{Cl} isotopes are 77.5% and 22.5% respectively.

<u>Explanation:</u>

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i   .....(1)

Let the fractional abundance of _{17}^{35}\textrm{Cl} isotope be 'x'. So, fractional abundance of _{17}^{37}\textrm{Cl} isotope will be '1 - x'

  • <u>For _{17}^{35}\textrm{Cl} isotope:</u>

Mass of _{17}^{35}\textrm{Cl} isotope = 35 amu

Fractional abundance of _{17}^{35}\textrm{Cl} isotope = x

  • <u>For _{17}^{37}\textrm{Cl} isotope:</u>

Mass of _{17}^{37}\textrm{Cl} isotope = 37 amu

Fractional abundance of _{17}^{37}\textrm{Cl} isotope = 1 - x

Average atomic mass of chlorine = 35.45 amu

Putting values in equation 1, we get:

35.45=[(35\times x)+(37\times (1-x))]\\\\x=0.775

Percentage abundance of _{17}^{35}\textrm{Cl} isotope = 0.775\times 100=77.5\%

Percentage abundance of _{17}^{37}\textrm{Cl} isotope = (1-0.775)=0.225\times 100=22.5\%

Hence, the percentage abundance of _{17}^{35}\textrm{Cl} and _{17}^{37}\textrm{Cl} isotopes are 77.5% and 22.5% respectively.

6 0
3 years ago
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