Explosives are chemicals that have very fast burn rates at different degree.
First the Dynamite:
-The dynamite is an explosive that made from nitroglycerin, and it is a type of the explosive that has a fast burning rate and makes it very strong explosive. Physical shock can make the dynamite to explode and makes it highly dangerous.
-But the fireworks are a class of low explosive, the stuff that used in it is black powder.Because this explosive has a slow burn rate than dynamite that makes it less dangerous and safer than dynamite explosives
-SO although the dynamite and the fireworks are both explosives they have different burn rates which make them totally different in safeness.
Answer: The parchments is 3200 years old.
Explanation: The carbon-14 is radioactive with a half-life (t1/2) of 5730 years. This means that it will take 5730 years for an initial sample of the isotope is reduced to its half. Because of it, Carbon-14 can be used to determine the age of an object.
From the question, "68% as much 14C radioactivity as plant material today" means that there is still 68% of the initial sample of the isotope. To determine how many half-lives passed in that period of time, you use:
A = A₀·
, in which
A is the amount left after a period of time;
A₀ is the initial amount;
n is the number of half-lives passed in the same period
It's known the remaining amount: A =
·A₀.
Substituing and calculating:
·A₀ = A₀·
0.68 = 
㏑0.68 = ㏑
- 0.387 = n·( - 0.693)
n = 
n = 0.558
n is the amount of half-lives passed and it can be written as:
n =
, where:
t is the period of time;
t1/2 is the half-life;
n =
t = n · t1/2
t = 0.558 . 5730
t = 3200 years
The parchment is approximately 3200 years of age.
Answer:
a. 1s2 2s2 2p6 3s2 3p6 4s2 3d 9 - the element is zinc and this is an excited state configuration
b. 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p6 6s2 4f 14 5d7 -the element is iridium and this is a ground state configuration
Explanation:
The ground state is the lowest energy state of an atom while excite states of Zn atom are higher energy states.
The configuration, 1s2 2s2 2p6 3s2 3p6 4s2 3d 9 applies to zinc atom in excited state while the configuration 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p6 6s2 4f 14 5d7 applies to iridium atom in ground state.
Answer:c
Explanation: just took the test
dont know sorry aaaaaaaaa