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gulaghasi [49]
3 years ago
12

A driver of a car traveling at 15.0 m/s applies the brakes, causing a uniform acceleration of -2.0 m/s/s. How long does it take

the car to come to a stop? Use the GUESS method. Please help me asap.
Physics
1 answer:
Maksim231197 [3]3 years ago
3 0
For this, we will use the formula:

<span>a = [V₀⁻V₁]÷t

</span>Where:

a - Acceleration
<span>V₀ - Final Velocity
</span>V₁ - Initial Velocity
<span>t - Time

</span>Given:
a = -2.0 m/s²
V₁ = 15.0 m/s
V₀ = 0 m/s ; because the car stopped

Find:
t = ?

Solution:

a = [V₀⁻V₁]÷t

First, we should derive the formula to the element that we are looking for (which is time).

t = [V₀⁻V₁]÷a
t = [0 m/s - 15.0 m/s]÷(-2.0 m/s²) ; substituting the numbers
t = -15.0 m/s ÷ -2.0m/s²
t = 7.5 seconds ; cancelling the removable units thus resulting only to the time unit s(seconds)

It took the car 7.5 seconds to stop
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The total consumption of electrical energy in the United States is about 1.0 1019 joules per year.
dexar [7]

Answer:

a) 316880878140.2895 Joules

b) 1056.26 Joules

c) 372.80103310622 km²

Explanation:

Energy consumption

E=\frac{P}{t}\\\Rightarrow E=\frac{1\times 10^{19}}{365.25\times 24\times 60\times 60}\\\Rightarrow E=316880878140.2895\ W

Average rate of electrical energy consumption is 316880878140.2895 Joules

Total population = 300 million

E=\frac{316880878140.2895}{300\times 10^6}\\\Rightarrow E=1056.26\ J

Each person consumes 1056.26 Joules.

Efficiency = 0.85

Power from Sun

0.85\times 1000=850\ W/m^2

Area

\frac{316880878140.2895}{850}=372801033.10622\ m^2

Converting to km²

372801033.10622=\frac{372801033.10622}{1000\times 1000}=372.80103310622\ km^2

Area required to collect the electrical energy used in the United States is 372.80103310622 km²

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Read 2 more answers
To hide their loot, thieves put the 1.20 kg gold that they had robbed into a small box and threw it in a lake. The mass of the e
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Answer:

11.1 cm

Explanation:

Let d be the depth upto which box dipped into water.

Volume of water displaced

.12\times .12\times d m^3\\

=.0144d

Weight of water displaced = upthrust

=.0144d\times 10^3\times g\\    [ density of water is 1000kg /m³]

=14.4dg This will act upwards.

Total downward force = 1.2 +.4 = 1.6 g

For equilibrium

1.6g = 14.4 gd

d = .111 m

=11.1 cm.

3 0
3 years ago
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