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Nataly_w [17]
3 years ago
14

13.4. Young's modulus for iron is 1.9 x 10' Pa. When an iron wire 1.0 m long with a cross-sectional area of 4.0 mm

Physics
1 answer:
Viefleur [7K]3 years ago
6 0

Answer:

0.0129 m

Explanation:

ΔL = FL / (EA)

where ΔL is the deflection,

F is the force,

L is the initial length,

E is Young's modulus,

and A is the cross sectional area.

F = mg = 100 kg × 9.8 m/s² = 9800 N

A = 4.0 mm² × (1 m / 1000 mm)² = 4×10⁻⁶ m²

ΔL = (9800 N) (1.0 m) / ((1.9×10¹¹ Pa) (4×10⁻⁶ m²))

ΔL = 0.0129 m

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Describe the organization of our solar system. What are the different divisions, or categories?
olasank [31]
Hello.

The solor system is organized by the smallest star to the largest and by the 8 planets. it is also organized by how much gas a planet has. But it is also orgainzed becasue of gravity.

The different divisions are <span>planets, moons, asteroids, comets and meteoroids.
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Have a nice day

6 0
3 years ago
Solve for the BMI weight 58kg Height 1.61​
vaieri [72.5K]

Answer:

Explanation:

BMI= weight/(height × height)          ; weight in kilogram and height in metter

     = 58kg / (1.61m  × 1.61m )

     = (58/ 2.5921) kg/m^{2}

     = 22.375  kg/m^{2}

     ≈ 22.4 kg/m^{2}

7 0
2 years ago
Two point charges of equal magnitude are 8.0 cm apart. At the midpoint of the line connecting them, their combined electric fiel
bagirrra123 [75]

Answer:

r = 8/2 = 4cm = 0.04m

k = 9×10^9

Enet = 51 N/C

Enet = E1 + E2

since E1 = E2

E1 = Enet/2 = 51/2

E/2 = kq/r²

q = Er²/2k

q = (51 × 0.04²)/(2×9×10^9)

q = 4.5×10^-12 C

q1 = q2 = 4.5 pC

Explanation:

The electric field is a region around a

charge in which it exerts electrostatic force

on another charges. While the strength of

electric field at any point in space is called

electric field intensity. It is a vector

quantity. Its unit is NC¯¹.

According to coulomb’s law ,if a unit

positive charge q (call it a test charge) is

brought near a charge q (call a field

charge) placed in space,the charge q will

experience a force. The value of this force

depends upon the distance between the

two charges. If the charge q is moved

away from q ,this force would decrease till

at a certain distance the force would be

practically reduced to zero. The charge q

is then out of the influence of charge q.

The region of space surrounding the charge

q in which it exerts a force on the charge

q is known as E.F of the charge

q. Mathematically it is expressed as:

E =F/q

The direction of the vector E is the same

as the direction of F,because q is a

positive scalar. Dimensionally,the E.F is

force per unit charge,and its SI unit is the

newton/coulomb (N/C).

7 0
3 years ago
CN you help me with this question?
qaws [65]
25% i believe because if were talking 50 percent half it would be 25.


8 0
3 years ago
A ray of violet light has a wavelength of about 4.2×10−7 m. will exposure to violet light cause electrons to be emitted from ces
lesantik [10]
The wavelength of violet light is given as 4.2x10^-7 m and the speed of light is 3x10^8 m/sec

The equation relating between the frequency and the wavelength is as follows:
speed of light = wavelength x frequency

Substitute with the givens in the above equation to get the frequency of violet light as follows:
frequency = (3 x 10^8) / (4.2 x 10^-7) = 7.14285 x 10^14 Hz

The threshold frequency of cesium is <span>9.39x10^14 Hz.
Since the frequency of violet light is less than the threshold frequency of cesium, therefore, the exposure to violet light won't </span><span>cause electrons to be emitted from cesium.</span>
7 0
3 years ago
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