Question

The vertical component of a vector is 40 N and its horizontal component is 25 N. What is the magnitude of the vector? A. 5.0 N B. 31.2 N C. 47.2 N D. 65.0 N

Answer 1

Answer:

The correct answer is option C.

Explanation:

$R=\sqrt{x^2+y^2}$

r = resultant vector

y = vertical component of vector

x = horizontal component of vector

We have :

The vertical component of a vector is 40 N and its horizontal component is 25 N.

x = 25 N

y = 40 N

$R=\sqrt{(25 N)^2+(40 N)^2}$

$R = 47.17 N \approx 47.2 N$

47.2 N is the magnitude of the vector.

Answer 2

The correct answer is C) 47.2 N i took the test and got it correct