<span>So we want to know how much clay did Joseph add after he built the cone. So the formula for the volume of the cone is V=(1/3)*pi*r^2*h where r is the radius and h is height. We know h1=12cm and r1=6cm, r2=6cm and h2=18 cm. So to get the amount of added clay Va we simply subtract the volume of the clay of the first cone V1 from the volume of the second cone V2: Vd=V2-V1=(1/3)*pi*(r1^2)*h1 - (1/3)+pi*(r2^2)*h2. Va=678.24 cm^3-452.39 cm^3= 266.08 cm^3.</span>
Answer:
A reflection over the x-axis
Step-by-step explanation:
Answer:
C
Step-by-step explanation:
The scale factor is the ratio of corresponding sides, image to original, so
scale factor = = = → C
Answer:
x = -1,5
Step-by-step explanation:
2x² - 8x - 10
2x² - 10x + 2x - 10
2x(x - 5) + 2(x - 5)
(x - 5)(2x + 2)
x = 5 x = -2/2
x = -1,5
Answer:
Arc DE = 90°
m<GAB = 82°
Arc DC = 49°
Step-by-step explanation:
Given:
m<EAF = 74°
m<EAD = right angle = 90°
Arc BG = 82°
Required:
Arc DE,
<GAB, and
Arc DC
Solution:
Recall that the central angle measure = the intercepted arc measure.
Therefore:
✔️Arc DE = m<EAD
Arc DE = 90° (Substitution)
✔️m<GAB = arc BG
m<GAB = 82° (Substitution)
✔️Arc DC = m<CAD
Find m<CAD
m<CAD = ½(180 - m<GAB)
m<CAD = ½(180 - 82)
m<CAD = 49°
Arc DC = m<CAD
Arc DC = 49°