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Sunny_sXe [5.5K]
3 years ago
14

(3+5i)(4+4i) what is the correct answer for this

Mathematics
2 answers:
Scilla [17]3 years ago
7 0
(3 + 5i)(4 + 4i)=12 + 12i + 20i -20
The answer is: -8 + 32i
earnstyle [38]3 years ago
4 0
=12 + 12i + 20i + 20i squared Because complex numbers or 'i' squared is negative one it is like this when written in the form of a + bi: =12 + 32i - 20 =-8+ 32i
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Jenny can type 1,200 words in just 15 minutes. How many words can she types in anhour?
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She can type 4,800 words in one hour.
7 0
3 years ago
Find the length and width of a rectangle that has the given area and a minimum perimeter. Area: 162 square feet
Gnom [1K]

Answer:

The width and length of rectangle is 12.728 m

Step-by-step explanation:

Let the length of the rectangle = L

let the width of the rectangle = W

The subjective function is given by;

F(p) = 2(L + W)

F = 2L + 2W

Area of the rectangle is given by;

A = LW

LW = 162 ft²

L = 162 / W

Substitute in the value of L into subjective function;

f = 2l + 2w\\\\f = 2(\frac{162}{w} )+2w\\\\f = \frac{324}{w} + 2w\\\\\frac{df}{dw} = \frac{-324}{w^2} +2\\\\

Take the second derivative of the function, to check if it will given a minimum perimeter

\frac{d^2f}{dw^2}= \frac{648}{w^3} \\\\Thus, \frac{d^2f}{dw^2}>0, \ since,\frac{648}{w^3} >0 \ (minimum \ function \ verified)

Determine the critical points of the first derivative;

df/dw = 0

\frac{-324}{w^2} +2 = 0\\\\-324 + 2w^2=0\\\\2w^2 = 324\\\\w^2 = \frac{324}{2} \\\\w^2 = 162\\\\w= \sqrt{162}\\\\w = 12.728 \ m

L = 162 / 12.728

L = 12.728 m

Therefore, the width and length of rectangle is 12.728 m

3 0
3 years ago
It Says Minute At The End
Kisachek [45]

Answer:

1.368

Step-by-step explanation: 1.14x1.2=1.368

4 0
3 years ago
Which are correct representations of the inequality –3(2x – 5) < 5(2 – x)? Select two options.
chubhunter [2.5K]

The correct statements are options C and option D.

  • - 6x + 15 < 10 - 5x ⇒ 3rd answer
  • An open circle is at 5 and a bold line starts at 5 and is pointing to the right.
<h3 /><h3>What is inequality?</h3>

The relation between two expressions that are not equal, employing a sign such as ≠ ‘not equal to’, > ‘greater than, or < ‘less than.

The inequality is -3(2x - 5) < 5(2 - x)

At first, simplify each side

-3(2x - 5) = -3(2x) + -3(-5)

Remember (-)(-) = (+)

-3(2x - 5) = - 6x + 15

5(2 - x) = 5(2) + 5(-x)

Remember (+)(-) = (-)

5(2 - x) = 10 - 5x

- 6x + 15 < 10 - 5x

Subtract 15 from both sides

- 6x < -5 - 5x

Add 5x to both sides

- x < - 5

Remember the coefficient of x is negative, then when you divide both sides by it you must reverse the sign of inequality

The coefficient of x is -1

Divide both sides by -1

x > 5

Therefore the correct statements are options C and option D.

  • - 6x + 15 < 10 - 5x ⇒ 3rd answer
  • An open circle is at 5 and a bold line starts at 5 and is pointing to the right.

To know more about inequality follow

brainly.com/question/24372553

#SPJ1

4 0
2 years ago
drag the gray arrow so that it is pointing midway between horizontal and vertical, heading downward and toward the right. extend
alex41 [277]

The speed of the star as compared to the speed of the star relative to earth is the frequency of light emitted by the source.

A star moving away from the observer (say on Earth) will have its emitted light red-shifted (move to lower frequency), i.e., the spectrum moving to left if we consider the intensity of light is plotted as a function of frequency with the frequency increasing from left to right.

A star moving towards the observer (say on Earth) will have its emitted light blue-shifted (move to higher frequency), i.e., the spectrum moving to the right if we consider the intensity of light is plotted as a function of frequency with the frequency increasing from left to right.

A star moving perpendicular to the observer (say on Earth) will have its emitted light will no change with respect to the spectrum of the stationary star.

These are due to the Doppler effect, the equation of frequency detected by the observer as

f_o = f_s\sqrt{\frac{1-\beta }{1+\beta } } where \beta = \frac{v}{c}, v the relative velocity of the moving source (the star here), f^s is the frequency of light emitted by the source.

Hence the answer is the speed of the star as compared to the speed of the star relative to earth is the frequency of light emitted by the source.

To learn more about frequency click here brainly.com/question/26177128

#SPJ4

7 0
1 year ago
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