Answer:
Answer is given below:
Explanation:
<em>Given Data:</em>
mass = 80kg
acceleration = 4 ms
force = 800N
<em>Find out:</em>
friction = ?
<em>Formula</em><em>:</em>
F-friction = weight - f-net
<em>Solution:</em>
weight = (80)(10)
= 800 N
F-net = ma =(80)(4) = 320N
F-friction = weight - F-net
=800 N - 320N
=480N
<em>Answer</em> :
Friction = 480 N
Answer:
Ether and acetone are the liquids with the lowest viscosities at room temperature.
Explanation:
Answer:
12g KCl will be crystallized
Explanation:
To solve this problem you need to know solubility of KCl in water at 20°C is 34g per 100g of water.
That means the maximum concentration of KCl you can dissolve at 20°C in 200g of water is 34g×2 = 68g of KCl
As solution containing 80g of KCl, the extra KCl will be crystallized after cooling, that is:
80g of KCl - 68g of KCl = <em>12g KCl will be crystallized</em>
I hope it helps!
Answer:
= 36.185 °C
Explanation:
Using the combined gas law;
P1V1/T1 = P2V2/T2
In this case;
P1 = 0.87 atm
V1 = 6.0 cm³
T1 = ?
P2 = 0.52 atm
V2 = 10 cm³
T2 = 35 °C + 273 = 308 K
Therefore;
T1 = P1V1T2/P2V2
= ( 0.87 × 6.0 × 308)/( 0.52 ×10)
= 309.185 K
Therefore; Initial temperature = 309.185 K - 273 = 36.185 °C