Answer:
99.24%.
Explanation:
- NaCl reacted with AgNO₃ as in the balanced equation:
<em>NaCl + AgNO₃ → AgCl(↓) + NaNO₃,</em>
1.0 mol of NaCl reacts with 1.0 mol of AgNO₃ to produce 1.0 mol of AgCl and 1.0 mol of NaNO₃.
- We need to calculate the no. of moles of AgCl produced:
no. of moles of AgCl = mass/molar mass = (2.044 g)/(143.32 g/mol) = 0.0143 mol.
- Now, we can calculate the no. of moles of NaCl that can precipitated as AgCl (0.0143 mol), these moles represents the no. of moles of pure NaCl in the sample:
<em>using cross multiplication:</em>
1.0 mol of NaCl produce → 1.0 mol of AgCl, from the stichiometry.
∴ 0.0143 mol of NaCl produce → 0.0143 mol of AgCl.
- Now, we can get the mass of puree NaCl in the sample:
mass of pure NaCl = (no. of moles of pure NaCl)(molar mass of NaCl) = (0.0143 mol)(58.44 g/mol) = 0.8357 g.
∴ The percentage of NaCl in the impure sample = [(mass of pure NaCl)/(mass of the impure sample)] x 100 = [(0.8357 g)/(0.8421 g)] x 100 = 99.24%.
<h3>
Answer:</h3>
CuO(s) + H₂(g) → Cu(s) + H₂O(l)
<h3>
Explanation:</h3>
- Assuming the reaction is the reduction of CuO by H₂
- Then the balanced equation for the reaction is;
CuO(s) + H₂(g) → Cu(s) + H₂O(l)
- The equation shows the reducing property of hydrogen gas, such that hydrogen reduces metal oxides such as copper(ii)oxide to the respective metals.
- The law of conservation requires chemical equations to be balanced so as the mass of reactants will be equal to that of products.
- In this case; there is 1 copper atom, 1 oxygen atom and 2 hydrogen atoms on both side of the equation and thus the equation is balanced.
Answer:
Cystic fibrosis (CF) is a genetic disease that causes thick, sticky mucus to build up in organs, including the lungs and the pancreas. In a healthy person, mucus that lines organs and body cavities, such as the lungs and the nose, is slippery and watery. In people with CF, thick mucus clogs causes symptoms in the lungs and pancreas.
Explanation:
The causes of CF
Who is affected
Symptoms and treatments
How CF is diagnosed in children and adults
Tips on living with CF
The volume of the stock solution that has a concentration of 1.5 M SO2 and is diluted to a 0.54 M solution with a volume of 0.18 L is 0.065L.
<h3>How to calculate volume?</h3>
The concentration of a solution can be calculated using the following formula:
C1V1 = C2V2
Where;
- C1 = initial concentration = 1.5M
- C2 = final concentration = 0.54M
- V1 = initial volume = ?
- V2 = final volume = 0.18L
1.5 × V1 = 0.54 × 0.18
1.5V1 = 0.0972
V1 = 0.0972 ÷ 1.5
V1 = 0.065L
Therefore, the volume of the stock solution that has a concentration of 1.5 M SO2 and is diluted to a 0.54 M solution with a volume of 0.18 L is 0.065L.
Learn more about volume at: brainly.com/question/1578538
a ceramic or metal container in which metals or other substances may be melted or subjected to very high temperatures.
"the crucible tipped and the mold filled with liquid metal"
a situation of severe trial, or in which different elements interact, leading to the creation of something new.
"their relationship was forged in the crucible of war"
