Answer: 
Explanation:
Given
Water column height 
After oil is poured, the total height becomes 
Pressure at the bottom will be the sum due to the water and oil column
Suppose the density of the oil is 
Pressure at the bottom
![\Rightarrow P=10^3\times g\times 25+900\times g\times 15\\\Rightarrow P=100g[250+135]\\\Rightarrow P=3773\times 100\ Pa\\\Rightarrow P=377.3\ kPa](https://tex.z-dn.net/?f=%5CRightarrow%20P%3D10%5E3%5Ctimes%20g%5Ctimes%2025%2B900%5Ctimes%20g%5Ctimes%2015%5C%5C%5CRightarrow%20P%3D100g%5B250%2B135%5D%5C%5C%5CRightarrow%20P%3D3773%5Ctimes%20100%5C%20Pa%5C%5C%5CRightarrow%20P%3D377.3%5C%20kPa)
Answer:
L = 5,955 m
Explanation:
For this exercise we must use the relation
R = ρ L / A
where R is the resistance that indicates that it is 1 Ω, the resistivity is taken from the tables ρ = 2.82 10⁻⁸ Ω m, L is the length of the wire and A is the cross section.
As it indicates to us in volume of aluminum to use we divide the two terms by the length
R / L = ρ L / (A L)
the volume of a body is its area times its length, therefore
R / L = ρ L / V
R = ρ L² / V
we clear the length of the wire
L = √ R V /ρ
we reduce the volume to SI units
v = 1 cm³ (1m / 10² cm)³ = 1 10⁻⁶ m
let's calculate
L = √ (1 1 10⁻⁶ / 2.82 10⁻⁸)
L = √ (0.3546 10²)
L = 5,955 m
Answer:
0.54
Explanation:
Draw a free body diagram. There are 5 forces on the desk:
Weight force mg pulling down
Applied force 24 N pushing down
Normal force Fn pushing up
Applied force 130 N pushing right
Friction force Fnμ pushing left
Sum of the forces in the y direction:
∑F = ma
Fn − mg − 24 = 0
Fn = mg + 24
Fn = (22)(9.8) + 24
Fn = 240
Sum of the forces in the x direction:
∑F = ma
130 − Fnμ = 0
Fnμ = 130
μ = 130 / Fn
μ = 130 / 240
μ = 0.54
Answer:
given,
children on left shore pulls the rope by 3 N
Children on the right shore pulls the rope by 2 N
speed of the box = 3 m/s
a) Power = Force x Velocity
Power = 3.0 N * 3
Power = 9 Watt
Power = 2.0 N x 3
Power = 6 Watt
b) Net Force = 3.0 N - 2.0 N = 1.0 N
Net Power = 1.0 x 3 Watt
Net Power = 3 Watt
c) net force is acting on the box and at an instant velocity is given so, when the body moves it will accelerate and velocity will change so, the value of part A and B will also change