Question

To the nearest tenth, what is the area of the shaded segment when JA=8ft ??

Answer 1

$A=\dfrac{1}{6}\pi 8^2-\dfrac{8^2\sqrt{3}}{4}\approx 5.8\;[ft^2]$
Answer: C. 5.8 ft squared

Answer 2

Answer : The area of the shaded segment is 5.8 ft squared.

Explanation :

Given that,

Length of JA = 8 ft

We have to find the area of the shaded segment. It is given by :

Area of the shaded segment = area of sector - area of the triangle

$A_{seg}=\dfrac{\theta}{360}\pi r^2-\dfrac{1}{2}r^2sin\theta$

$A_{seg}=\dfrac{60}{360}\times \dfrac{22}{7}\times (8)^2-\dfrac{1}{2}\times (8)^2sin60$  

$A_{seg}=5.8\ ft^2$

or

$A_{seg}=5.8\ ft\ squared$

So, the correct option is (C) " 5.8 ft squared".