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Natasha2012 [34]
3 years ago
13

To the nearest tenth, what is the area of the shaded segment when JA=8ft ??

Physics
2 answers:
Murrr4er [49]3 years ago
7 0
A=\dfrac{1}{6}\pi 8^2-\dfrac{8^2\sqrt{3}}{4}\approx 5.8\;[ft^2]
Answer: <span>C. 5.8 ft squared</span>
Nikitich [7]3 years ago
7 0

Answer : The area of the shaded segment is 5.8 ft squared.

Explanation :

Given that,

Length of JA = 8 ft

We have to find the area of the shaded segment. It is given by :

Area of the shaded segment = area of sector - area of the triangle

A_{seg}=\dfrac{\theta}{360}\pi r^2-\dfrac{1}{2}r^2sin\theta

A_{seg}=\dfrac{60}{360}\times \dfrac{22}{7}\times (8)^2-\dfrac{1}{2}\times (8)^2sin60  

A_{seg}=5.8\ ft^2

or

A_{seg}=5.8\ ft\ squared

So, the correct option is (C) " 5.8 ft squared".

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log₁₀r  = 3.9 /2

log₁₀r = 1.95

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Therefore, the required distance is 89.125 m

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