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mylen [45]
3 years ago
15

A wire that has a resistance of 1Ω is to be built from an aluminum block of volume 1 cm3

Physics
1 answer:
alina1380 [7]3 years ago
5 0

Answer:

  L = 5,955 m

Explanation:

For this exercise we must use the relation

        R = ρ L / A

where R is the resistance that indicates that it is 1 Ω, the resistivity is taken from the tables ρ = 2.82 10⁻⁸ Ω m, L is the length of the wire and A is the cross section.

As it indicates to us in volume of aluminum to use we divide the two terms by the length

    R / L = ρ L / (A L)

the volume of a body is its area times its length, therefore

  R / L = ρ L / V

  R = ρ L² / V

we clear the length of the wire

   L = √ R V /ρ

we reduce the volume to SI units

   v = 1 cm³ (1m / 10² cm)³ = 1 10⁻⁶ m

let's calculate

   L = √ (1  1  10⁻⁶ / 2.82 10⁻⁸)

   L = √ (0.3546 10²)

   L = 5,955 m

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Answer:

thermomiter

Explanation:

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Incorrect i think! it’s definitely not accurate or precise
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The drawing shows a hydraulic chamber with a spring (spring constant = 1600 N/m) attached to the input piston and a rock of mass
Triss [41]

Answer:

\Delta x=245\ mm

Explanation:

Given:

  • spring constant of the spring attached to the input piston, k=1600\ N.m^{-1}
  • mass subjected to the output plunger, m=40\ kg

<u>Now, the force due to the mass:</u>

F=m.g

F=40\times 9.8

F=392\ N

<u>Compression in Spring:</u>

\Delta x=\frac{F}{k}

\Delta x=\frac{392}{1600}

\Delta x=0.245\ m

or

\Delta x=245\ mm

8 0
4 years ago
A sports car has an average acceleration of 5.81 m/s2. How long does it take for the car to reach 60.0 mi/h, if it starts from r
Aleks04 [339]

Answer:

  4.617 s

Explanation:

The speed of 60 mi/h can be converted to m/s:

  (60 mi/h) × (1609.344 m/mi) × (1 h)/(3600 s) = 26.8244 m/s

The relationship between speed and acceleration is ...

  v = at

  t = v/a = (26.8244 m/s)/(5.81 m/s²) ≈ 4.617 s

It will take the car 4.617 seconds to reach 60 mi/h starting from rest.

5 0
3 years ago
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The mass of Tesla Model S is 2000 kg and its engine produces
yulyashka [42]

Answer:

The ratio of the power generated by the engines are \dfrac{2}{3}

(b) is correct option.

Explanation:

Given that,

Mass of Tesla = 2000 Kg

Torque = 400 Nm

Mass of Mercedes = 1.5 M Tesla

The Benz engine produces 50% more torque than the Tesla.

We need to calculate the power generated by the engines 6 seconds after a start from rest

Using formula of  power

P=F\cdot v

We know that,

v=at

v=\dfrac{F}{m}t

v=\dfrac{\tau}{mr}t

Put the value of F and v in equation (I)

P=\dfrac{\tau}{r}\times\dfrac{\tau}{mr}t

P=\dfrac{\tau^2t}{mr^2}

Here, r and t are same for both bodies.

P\propto\dfrac{\tau^2}{m}

We need to calculate the ratio of the power generated by the engines

Using formula of power

\dfrac{P_{T}}{P_{B}}=\dfrac{\tau_{T}^2}{m_{T}}\times\dfrac{m_{B}}{\tau_{B}}

Put the value into the formula

\dfrac{P_{T}}{P_{B}}=\dfrac{400^2}{2000}\times\dfrac{3000}{600^2}

\dfrac{P_{T}}{P_{B}}=\dfrac{2}{3}

Hence, The ratio of the power generated by the engines are \dfrac{2}{3}

3 0
3 years ago
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