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3 years ago

Which graphic design tools help you draw circles and rectangles?

Physics

1 answer:

Lubov Fominskaja [6]3 years ago

7 0

Geometric Shape Tools
Hope this helps :)

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On a typical clear day, the atmospheric electric field points downward and has a magnitude of approximately 103 N/C. Compare the

Nina [5.8K]

Answer:

a) FE = 0.764FG

b) a = 2.30 m/s^2

Explanation:

a) To compare the gravitational and electric force over the particle you calculate the following ratio:

$\frac{F_E}{F_G}=\frac{qE}{mg}$ (1)

FE: electric force

FG: gravitational force

q: charge of the particle = 1.6*10^-19 C

g: gravitational acceleration = 9.8 m/s^2

E: electric field = 103N/C

m: mass of the particle = 2.2*10^-15 g = 2.2*10^-18 kg

You replace the values of all parameters in the equation (1):

$\frac{F_E}{F_G}=\frac{(1.6*10^{-19}C)(103N/C)}{(2.2*10^{-18}kg)(9.8m/s^2)}\\\\\frac{F_E}{F_G}=0.764$

Then, the gravitational force is 0.764 times the electric force on the particle

The acceleration of the particle is obtained by using the second Newton law:

$F_E-F_G=ma\\\\a=\frac{qE-mg}{m}$

you replace the values of all variables:

$a=\frac{(1.6*10^{-19}C)(103N/C)-(2.2*10^{-18}kg)(9.8m/s^2)}{2.2*10^{-18}kg}\\\\a=-2.30\frac{m}{s^2}$

hence, the acceleration of the particle is 2.30m/s^2, the minus sign means that the particle moves downward.

7 0

3 years ago

Can u answer 4 and 5 for me

Luda [366]

I don’t know what the answers are

8 0

4 years ago

The Environmental Protection Agency has ben concerned about the levels of radon gas in homes. If a sample of gas taken from a ba

soldier1979 [14.2K]

Answer is 2.19 g of radon will remain in the sample after 4 half-lives

6 0

3 years ago

Which of the following statements is NOT true? A. You are exposed to nuclear radiation every day. B. Most of the nuclear radiati

tia_tia [17]

C is not true. Background radiation is the uniform microwave radiation remaining from the Big Bang.

5 0

3 years ago

A car accelerates uniformly from rest to a speed of 7.6 m/s in 4.6 s. How far does the car travel in that time?

uysha [10]

Answer:

The car will travel a distance of 17.45 meters.

Explanation:

Given:

Initial velocity $(V_i)$ = 0

Final velocity $(V_f)$ = 7.6 m/s

Time taken = 4.6 s

Acceleration = (Final velocity - Initial Velocity )/time

$a=\frac{(V_f-Vi)}{t}= \frac{7.6-0}{4.6}=1.65\ ms^-2$

We have to calculate total distance traveled by the car.

Let the distance traveled be 'd'

Equation of motion:

$d=V_i(t)+\frac{at^2}{2}$

Plugging the values.

⇒ $d=V_i(t)+\frac{at^2}{2}$

⇒ $d=0+\frac{1.65*(4.6)^2}{2}$

⇒ $d=17.45\ m$

The car will travel a distance of 17.45 meters for the above case.

4 0

3 years ago