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aliina [53]
3 years ago
8

Whats potential energy?

Physics
2 answers:
Kitty [74]3 years ago
7 0

potential energy is the energy held by an object because of its position relative to other objects, stresses within itself, its electric charge, or other factors.

aliina [53]3 years ago
5 0

Answer:

Potential energy is the latent energy in an object at rest, and is one of two forms of energy. The other form, kinetic energy, is the energy expressed by an object in motion. The actual potential energy of an object depends on its position relative to other objects.

Explanation:

You might be interested in
Which equation relates charge, time, and current?
Ierofanga [76]

Answer:

I = Δq / t

Explanation:

The quantity of electricity i.e charge is related to current and time according to the equation equation:

Q = It

Δq = It

Where:

Q => is the quantity of electricity i.e charge

I => is the current.

t => is the time.

Thus, we can rearrange the above expression to make 'I' the subject. This is illustrated below:

Δq = It

Divide both side by t

I = Δq / t

6 0
2 years ago
n 38 g rifle bullet traveling at 410 m/s buries itself in a 4.2 kg pendulum hanging on a 2.8 m long string, which makes the pend
Kitty [74]

Answer:

68cm

Explanation:

You can solve this problem by using the momentum conservation and energy conservation. By using the conservation of the momentum you get

p_f=p_i\\mv_1+Mv_2=(m+M)v

m: mass of the bullet

M: mass of the pendulum

v1: velocity of the bullet = 410m/s

v2: velocity of the pendulum =0m/s

v: velocity of both bullet ad pendulum joint

By replacing you can find v:

(0.038kg)(410m/s)+0=(0.038kg+4.2kg)v\\\\v=3.67\frac{m}{s}

this value of v is used as the velocity of the total kinetic energy of the block of pendulum and bullet. This energy equals the potential energy for the maximum height reached by the block:

E_{fp}=E_{ki}\\\\(m+M)gh=\frac{1}{2}mv^2

g: 9.8/s^2

h: height

By doing h the subject of the equation and replacing you obtain:

(0.038kg+4.2kg)(9.8m/s^2)h=\frac{1}{2}(0.038kg+4.2kg)(3.67m/s)^2\\\\h=0.68m

hence, the heigth is 68cm

4 0
3 years ago
Which two charges of a magnet will attract?
ale4655 [162]

Answer:

The other end is called the south pole. When two magnets are brought together, the opposite poles will attract one another, but the like poles will repel one another. This is similar to electric charges.

Explanation:

4 0
2 years ago
Read 2 more answers
Two point sources, vibrating in phase, produce an interferencepattern in a ripple tank. If the frequency is increased by 20%, th
Vera_Pavlovna [14]

Answer:

option A

Explanation:

given,

frequency is increased by 20%

we know,

\dfrac{x_n}{L}d = (n-\dfrac{1}{2})\times \lambda...........(1)

where

x_n is the perpendicular distance between the point the interference pattern is obtained,

L is the distance between the center of the two point sources

and λ is  the wavelength of light.

If the frequency is increased by 20%, then the number of nodal lines is increased by 20%.

From equation (1),we observe that the frequency is directly proportional to the number of nodal lines.

Hence, the correct answer is option A

8 0
2 years ago
A bullet with mass m = 0.1 kg grams hits a ballistic pendulum with length L = 3 meters and mass M = 2 kg and lodges in it. When
Mnenie [13.5K]

Answer:

e)     v₁ = 29.7 m / s

Explanation:

Let's propose the solution of the problem, let's start at the moment

Initial

        p₀ = m v₁

Final

     p_{f} = (m + M) v

The moment is preserved

      p₀ =  p_{f}

      m v₁ = (m + M) v

      v = m / (m + M) v₁        (1)

a) energy is conserved

Let's look for kinetic energy

Initial

      K₀ = ½ m v₁²

Final

      K_{f} = ½ (m + M) v²

Let's replace v

     K_{f} = ½ (m + M) [m / (m + M) v₁]²

      K_{f} = ½ m² / (m + M) v₁²

Let's look for the relationship of these energies

     Ko / K_{f} = ½ m v₁² / (½ m² / (m + M) v₁²)

     Ko / K_{f}= (m + M) / m = (1 + M / m)²

The kinetic energy changes therefore it is not conserved in the process, the missing energy is converted into potential heat energy during the crash

b) The impulse is conserved because the system is defined as formed by the two bodies and the externals are of action and reaction, so for the complete system the sum is zero and the moment does not change in value

c) in this case the system is already formed by the two bodies and since there is no rubbing the mechanical energy is conserved, transforming from kinetics to potential

d) when the pendulum oscillates the speed changes from v to zero, so the moment is not conserved, this is because there is an external force acting on the system, the force of gravity

e) For this part let's start at the end of the movement

It is system (bullet + block) moves, energy is conserved

Final. Highest point

          Em_{f} = U = (m + M) g h

Initial. Lowest point

          Em₀ = K = ½ (m + M) v2

          Em₀ =  Em_{f}

          ½ (m + M) v² = (m + M) g h

          v = √ 2gh

Let's look for the height (h) by trigonometry

         Cos 15 = x / L

          h = L-x

          h = L - L cos 15

          h = L (1- cos 15)

We replace

          v = √ (2gL (1- cos 15))

Now we use equation (1) of momentum conservation

         v = m / (m + M) v1

         v₁ = (m + M) / m v

         v1 = (0.1 +2.0) /0.1 RA (2 9.8 3 (1- cos 15))

         v₁ = 21 √ (2.00)

        v₁ = 29.7 m / s

6 0
3 years ago
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