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Svet_ta [14]
3 years ago
7

Which pair below describes isotopes of the same element? A) an atom with 6 protons and 8 neutrons - an atom with 8 protons and 6

neutrons B) an atom with 6 protons and 6 neutrons - an atom with 6 protons and 7 neutrons C) an atom with 8 protons and 8 neutrons - an atom with 7 protons and 8 neutrons D) an atom with 7 protons and 6 neutrons - an atom with 6 protons and 6 neutrons
Chemistry
1 answer:
V125BC [204]3 years ago
8 0

<u>Answer:</u> The atom with 6 protons and 6 neutrons and an atom with 6 protons and 7 neutrons are the isotopes of same element.

<u>Explanation:</u>

Isotopes are defined as the chemical species that belong to the same element but differ in their mass number.

This also means that the chemical species have same number of protons and electrons but different number of neutrons.

Atomic number is defined as the number of protons or electrons that are present in a neutral atom.

Atomic number = number of protons = number of electrons

Mass number is defined as the sum of number of protons and neutrons that are present in an atom.

Mass number = Number of protons + Number of neutrons

From the given options:

The elements having same number of protons will be the isotopes of same element.

Hence, the atom with 6 protons and 6 neutrons and an atom with 6 protons and 7 neutrons are the isotopes of same element.

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he first solution contains 25 % acid, the second contains 35 % acid, and the third contains 55 % acid. She created 100 liters of
photoshop1234 [79]

Answer:

Volume of first solution       =  20 Liters

Volume of second solution =  20 Liters

Volume of third solution     =  60 Liters

Explanation:

Let the volume second solution  used= y

Let the volume of third solution used = 3y

Let the volume of first solution used = 100 - (y +3y)

                                                             = 100- 4y

The volume of acid in the first solution ( V₁)  = 25% of (100-4y)

                                                                         = 25-y

The volume of acid in the second solution(V₂)  =35% of y

                                                                              = 0.35y

The volume  acid in the  third solution (V₃)  = 55% of 3y

                                                                       =1.65y

The  Volume of acid in Mixture (V₄)   =   45% of 100

                                                             =  45

From the conservation of volume:

V₄ =  V₁  +  V₂ + V₃

45 = (25-y )+ 0.35y + 1.65y

45 =25 -y + 0.35y + 1.65y

45 -25 = y

y = 20

So the volume of first solution used = 100- 4y

                                                             = 100- 4(20)

                                                             =  20 Liters

So the volume of second solution used = y

                                                             =  20 Liters

So the volume of third solution used = 3y

                                                             =  3(20)

                                                             =  60 Liters

3 0
3 years ago
How many joules are required for melting 12.8g of ice at 0 degrees Celsius?
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Answer:

4,270 Joules

Explanation:

The heat of fusion of water is 334 j/g. So, the equation would be (12.8 g)(334 j/g) which comes to 4,270 joules.

Written out that's just twelve point eight times three hundred and thirty four.

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Answer: nais.. thanks

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