Answer:
Explanation:
We have the ideal gasses equation 
and the expression for the specific volume 
, that is the inverse of the density, and for definition the number of moles is equal to the mass over the molar mass, that is 
And we can relate the three equations as follows:
Replacing the expression for n, we have:
Replacing the expression for v, we have:
Now resolving for T, we have:
Now, we should convert all the quantities to the same units:
-Convert 500kPa to atm
-Convert 0.2
to 
- Convert the molar mass M of the water from 
to 
Finally we can replace the values:
Answer: The equilibrium constant is 
Explanation:
Initial concentration of 
= 0.095 M
The given balanced equilibrium reaction is,
Initial conc. 0.095 M 0 M
At eqm. conc. (0.095-x) M (2x) M
Given : 2x = 0.0055
x = 0.00275
The expression for equilibrium constant for this reaction will be,
![K_c=\frac{[l]^2}{[I_2]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5Bl%5D%5E2%7D%7B%5BI_2%5D%7D)
Now put all the given values in this expression, we get :
Thus the equilibrium constant is
Answer:
131 atm
Explanation:
To find the new pressure, you need to use Boyle's Law:
P₁V₁ = P₂V₂
In this equation, "P₁" and "V₁" represent the initial pressure and volume. "P₂" and "V₂" represent the final pressure and volume. You can find the new pressure (P₂) by plugging the given values into equation and simplifying.
P₁ = 3.88 atm P₂ = ? atm
V₁ = 7.74 L V₂ = 0.23 L
P₁V₁ = P₂V₂ <----- Boyle's Law
(3.88 atm)(7.74 L) = P₂(0.23 L) <----- Insert values
30.0312 = P₂(0.23 L) <----- Simplify left side
131 = P₂ <----- Divide both sides by 0.23
