Answer: 81.85 km/hr
Converting m/sec into km/hr, 25 m/sec = 90 km/hr
Average =
Time = 50/90 = 5/9 hr
next 120 km at an average speed of 80km/h
=> Time = 120/80 = 3/2 hr
last part of its journey at an average speed of 90km/h in 35 Minutes
time = 35 minutes = 35/60 hr = 7/12 hr
Distance covered = 90 * 7 /12 = 105/2 km
Total Distance = 50 + 120 + 105/2 = 435/2 km
Total time = 5/9 + 3/2 + 7/12 = ( 20 + 54 + 21) /36 = 95/36
Average speed = (435/2)/(95 /36) = 432 * 18 /95 = 81.85 km/hr
Answer:
i think that the answers is -16x + 5
8. It is divisible by both 32 and 40.
Answer: 3H+4C<_ 30
The coefficients of the variables H and C represent the number of batteries each toy helicopter and each toy car uses.
Step-by-step explanation:
Each toy helicopter uses 3 batteries, and each toy car uses 4 batteries.
Now let's check whether Vugar has enough batteries for 5 toy helicopters and 4 toy cars. To do this, we substitute H=5 and C= 4 in the given inequality:
Does Vugar have enough batteries to play with 5 toy helicopters and 4 toy cars?
No, because if you plug in the value for H and C:
3H + 4C<_ 30
3(5) + 4(4) <_30
15 + 16 <_ 30
31 <_ 30; false
Since the inequality is false, Vugar does not have enough batteries to play with 555 toy helicopters and 444 toy cars.
Each toy helicopter uses 333 batteries, and each toy car uses 444 batteries.
No, Vugar does not have enough batteries to play with 555 toy helicopters and 444 toy cars.
Answer: r= 25/3
Step-by-step explanation:
r-4(r+6)=-49 distribute the 4
r-4r-24=-49 combine like terms
-3r-24=-49 add 24 to both sides
-3r=-25 divide by -3
r= 25/3 answer
