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Makovka662 [10]
3 years ago
5

Balance CH4+O2->CO2+H2O

Chemistry
1 answer:
malfutka [58]3 years ago
5 0

Explanation:

I hope this helps Chemistry is so hard and I hate it

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Which of these pairs of elements have the same number of valence electrons?
Taya2010 [7]
The same number of valence electrons exists in the same family of elements in the periodic table. In finding the answer to this problem, we just have to find the pair that belongs to the same family in the periodic table. The same family means same column. Among these, Oxygen and lead (Pb) are in the same family. This pair is the answer.
7 0
3 years ago
How many mols of a 3M NaOH solution are in 1L of the solution?
Alex

To calculate this, we need the Molarity formula. This formula tell us that Molarity, which is a concentration unit, is equal to the number of moles divided by the volume. In this question we already have the Molarity and the Volume, so let's build our equation:

C = n/V (You can see Molarity with the letter "C" because it means concentration)

3 = n/1

n = 1 * 3

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6 0
1 year ago
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Arturiano [62]

Answer:

your answer is 12 hope it's correct answer

4 0
3 years ago
Give examples of how land resources are used in a city setting
poizon [28]

Answer:

Land resources such as gravel and bedrock are used to construct buildings, roads, and sidewalks. Land is also where city structures—such as buildings, roads, and sidewalks—are constructed. People use land resources such as bedrock and aggregate to construct buildings, roads, and sidewalks.

I hope this answer helps

5 0
3 years ago
Read 2 more answers
Suppose that a certain biologically important reaction is quite slow at physiological temperature (37 oC) in the absence of a ca
Oksi-84 [34.3K]

Answer:

30 kJ

Explanation:

Arrhenius equation is given by:

k=Aexp(-Ea/RT)\\

Here, k is rate constant, A is Pre-exponential factor, Ea is activation energy and T is temperature.

taking natural log of both side

ln k = ln A - Ea/RT

In Arrhenius equation, A, R and T are constant.

Therefore,

ln\frac{k_2}{k_1} =\frac{Ea_1-Ea_2}{RT}

Ea_1-Ea_2 is the  lowering in activation energy by enzyme,

R = 8.314 J/mol.K

T = 37°C + 273.15 = 310 K

\frac{k_2}{k_1} =1\times 10^5

ln 1\times 10^5 =\frac{Ea_1-Ea_2}{RT}\\{Ea_1-Ea_2} = 11.512 \times 8.314 \times 310\\=29670\ J\\=30\ kJ

4 0
3 years ago
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