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My name is Ann [436]
2 years ago
13

What do you call the maximum displacement of a wave from the equilibrium position?

Physics
1 answer:
weeeeeb [17]2 years ago
7 0
Personally, I call it the wave's "amplitude".

What do YOU call it ?
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Dave throws a 10 kg bowling ball straight up in the air. At the very tippy-top of its path, what is it's momentum?
svetoff [14.1K]

Answer:Zero

Explanation:

Given

mass of ball m=10\ kg

If the ball is thrown upward then at maximum point velocity of ball is zero because ball is no longer able to move upward

Momentum(P) of a particle is given by

P=mass\times velocity

P=10\times 0

P=0

Therefore at the highest point momentum is zero .

8 0
3 years ago
When the compasses are moved close to a wire with a current which will the compasses point
Sindrei [870]
<span>In this demonstration, there is a single compass and a piece of wire that is perpendicular to the plane that the compass sits on. The wire with current flowing through it can alter the direction the compass needle points.</span>
4 0
3 years ago
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Obtain a volume of 12.5 millimeters of liquid in the diagram
tiny-mole [99]

Answer:

D remove 1.5 ML of liquid.

Explanation:

     

5 0
2 years ago
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What is the area of the bottom of a tank 30.0 cm long and 15.0 cm wide?​
Igoryamba

Answer:

perimeter of the bottom of the tank is 450 cm

Explanation:

If you want to get area you need the Length, width,and height.

5 0
3 years ago
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A distant planet with a mass of (7.2000x10^26) has a moon with a mass of (5.0000x10^23). The distance between the planet and the
BARSIC [14]

Answer:

Explanation:

This is a simple gravitational force problem using the equation:

F_g=\frac{Gm_1m_2}{r^2} where F is the gravitational force, G is the universal gravitational constant, the m's are the masses of the2 objects, and r is the distance between the centers of the masses. I am going to state G to 3 sig fig's so that is the number of sig fig's we will have in our answer. If we are solving for the gravitational force, we can fill in everything else where it goes. Keep in mind that I am NOT rounding until the very end, even when I show some simplification before the final answer.

Filling in:

F_g=\frac{(6.67*19^{-11})(7.2000*10^{26})(5.0000*10^{23})}{(6.10*10^{11})^2} I'm going to do the math on the top and then on the bottom and divide at the end.

F_g=\frac{2.4012*10^{40}}{3.721*10^{23}} and now when I divide I will express my answer to the correct number of sig dig's:

Fg= 6.45 × 10¹⁶ N

8 0
3 years ago
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