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RideAnS [48]
3 years ago
12

9. A child standing on a bus remains still when the bus is at rest. When the bus moves forward and then slows down, the child co

ntinues moving
forward at the original speed. This is an example of
A. Newton's First Law of Motion
B. Newton's Third Law of Motion
C, an action-reaction par
D. Newton's Second Law of Motion
Physics
1 answer:
marin [14]3 years ago
3 0
I think the answer is C
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Two cars collide and come to a complete stop. where did all of their energy go?
MA_775_DIABLO [31]
Most of the energy will be absorbed by the materials that make up the cars, causing them to deform. The energy will also be converted into sound energy, causing a loud bang upon collision. Also, some energy will be converted to thermal energy, which will cause the cars to heat up slightly.
3 0
3 years ago
A 86 kg human stands on the surface of Venus. The mass of Venus is 4.9 × 1024 kg and its radius is 6.1 × 106 m. Collapse questio
iris [78.8K]

Answer:

755.37 N

Explanation:

We are given that

Mass of venus=m_1=4.9\times 10^{24}kg

Radius=r=6.1\times 10^6m

Mass of human=m_2=86 kg

We know that the gravitational force between two bodies

F=G\frac{m_1m_2}{r^2}

Where G=Gravitational constant=6.67\times 10^{-11}Nm^2/kg^2

Using the formula

The magnitude of the gravitational force exerted by Venus on the human=F=\frac{6.67\times 10^{-11}\times 86\times 4.9\times 10^{24}}{(6.1\times 10^6)^2}

The magnitude of the gravitational force exerted by Venus on the human=F=755.37N

7 0
3 years ago
Define Momentum in detail.
Harrizon [31]

Explanation:

Momentum Is defined as the product of of mass and its velocity

Momentum (M) =mass *velocity

SI unit of momentum is kgm/s

The rate of change in momentum

=change in momentum / time

=(mv-mu)/t

8 0
3 years ago
Read 2 more answers
A boy accidentally touch an electric cable and quickly withdrew his hand. Narrate the impulses involved in such action.
Lelechka [254]

Answer:

Quick action was in this as a thought of he knew he could die from this

3 0
3 years ago
Read 2 more answers
You hold a barbell in a horizontal position. The barbell’s center of mass is exactly mid-way between your two hands. A friend wa
Harrizon [31]

Explanation:

First consider that each hand works as a fulcrum: a pivot point where the barbell can rotate.

Now consider only the left hand. If the center of mass of the barbell is between hands (in the middle) it is displaced respect the fulcrum, therefore the weight which is pushing the bar downwards becomes a rotational force. The same thing happens to the other hand. Now, if more weight is added to the left hand the center of mass is displaced towards the left hand and depending how much weight is added, the center of mass will change its position and therefore the torque each hand experiences changes.

If the center of mass is still between hands: The torque remains almost the same changing only the magnitudes but not the direction.

If the center of mass is on the hand: there is no torque for the left hand because there is no leaver.

If the center of mass is to the left: now the torque changes direction and both hands need to stop it in the same direction.

(see diagram below)

6 0
3 years ago
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