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RideAnS [48]
3 years ago
12

9. A child standing on a bus remains still when the bus is at rest. When the bus moves forward and then slows down, the child co

ntinues moving
forward at the original speed. This is an example of
A. Newton's First Law of Motion
B. Newton's Third Law of Motion
C, an action-reaction par
D. Newton's Second Law of Motion
Physics
1 answer:
marin [14]3 years ago
3 0
I think the answer is C
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friction force is the opposition to the motion of surfaces sliding across each other. what is one factor that affects the amount
ruslelena [56]

Answer

Nature of the surfaces.


Explanation

Friction is the the force that opposes motion between two surfaces that are in relative motion. If two objects are in contact, one of it or both must be in motion for friction to exist.

Friction is affected by a number of factors.

One is the weight of the object. The more the weight of the object the higher the friction between it and the surface.

The other factor is the nature of the surfaces. Rough surfaces contribute to high friction while smooth surfaces reduces the friction between surfaces.  

3 0
2 years ago
In science, all concepts are
Dmitry [639]
Your answer will be C
6 0
3 years ago
Explain ALL THREE of Newton’s Laws in your own words.
Svet_ta [14]

Explanation:

(1) Every object moves in a straight line unless acted upon by a force. (2) The acceleration of an object is directly proportional to the net force exerted and inversely proportional to the object's mass. (3) For every action, there is an equal and opposite reaction.

5 0
2 years ago
A ball is released from a tower at a height of 100 meters toward the roof of another tower that is 25 meters high. The horizonta
ahrayia [7]
The answer is 5.11 meters/second
5 0
3 years ago
Read 2 more answers
In an old-fashioned amusement park ride, passengers stand inside a 4.9-m-diameter hollow steel cylinder with their backs against
Viefleur [7K]

Answer:

24.07415 rpm

Explanation:

\mu = Coefficient of friction = 0.63

v = Velocity

d = Diameter = 4.9 m

r = Radius = \frac{d}{2}=\frac{4.9}{2}=2.45\ m

m = Mass

g = Acceleration due to gravity = 9.81 m/s²

Here the frictional force balances the rider's weight

f=\mu F_n

The centripetal force balances the weight of the person

\mu m\frac{v^2}{r}=mg\\\Rightarrow \mu \frac{v^2}{r}=g\\\Rightarrow v=\sqrt{\frac{gr}{\mu}}\\\Rightarrow v=\sqrt{\frac{9.81\times 2.45}{0.63}}\\\Rightarrow v=6.17656\ m/s

Velocity is given by

v=\omega r\\\Rightarrow \omega=\frac{v}{r}\\\Rightarrow \omega=\frac{6.17656}{2.45}\\\Rightarrow \omega=2.52104\ rad/s

Converting to rpm

2.52104\times \frac{60}{2\pi}=24.07415\ rpm

The minimum angular speed for which the ride is safe is 24.07415 rpm

4 0
2 years ago
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