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RideAnS [48]
3 years ago
12

9. A child standing on a bus remains still when the bus is at rest. When the bus moves forward and then slows down, the child co

ntinues moving
forward at the original speed. This is an example of
A. Newton's First Law of Motion
B. Newton's Third Law of Motion
C, an action-reaction par
D. Newton's Second Law of Motion
Physics
1 answer:
marin [14]3 years ago
3 0
I think the answer is C
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A bicyclist in the Tour de France crests a mountain pass as he moves at 18 km/h. At the bottom, 4.0 km farther, his speed is at
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We are given:

v0 = initial velocity = 18 km/h

d = distance = 4 km

v = final velocity = 75 km/h

a =?

<span>
We can solve this problem by using the formula:</span>

v^2 = v0^2 + 2 a d

 

75^2 = 18^2 + 2 (a) * 4

5625 = 324 + 8a

<span>a = 662.625 km/h^2</span>

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Alan slides across home plate during a baseball game. If he has a mass of 61
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Answer:

D. 371 N

Explanation:

Friction force equals normal force times the coefficient of friction:

F = Nμ

Since the ground is level, normal force equals weight:

N = mg

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F = mgμ

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F = 371 N

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In an orbiting space shuttle, you are handed two identical boxes, one filled with sand and the other filled with feathers. How c
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Explanation:

Simply, shake the boxes. The box that is difficult to shake will be the sand and the box that will be easier will be the feathers.

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3 years ago
13. Now we will examine the electric field of a dipole. The magnitude and direction of the electric field depends on the distanc
Gennadij [26K]

This question is incomplete, the complete question is;

Now we will examine the electric field of a dipole. The magnitude and direction of the electric field depends on the distance and the direction. We will investigate in detail just two directions. With charges available in the simulation (all the charges are either positive or negative 1 nC increments).

how do you create a dipole with dipole moment 1 x 10-9 Cm with a direction for the dipole moment pointing to the right. Make a table below that shows the amounts of  charge and the distance between the charges. There are many correct answers

Answer:

Given the data in question;

Dipole moment P = 1 × 10⁻⁹ C.m

now dipole pointing to the right;

               P→

_{-\theta } (-) ---------------->(+) _{+\theta }

               d

so let distance between the dipoles be d

∴ P = d\Theta

Let \Theta_{1} = 1 nC

so

P = d\Theta

1 × 10⁻⁹ =  1 × 10⁻⁹  × d

d = (1 × 10⁻⁹) / (1 × 10⁻⁹)

d = 1 m

Also Let \Theta_{2} = 2 nC

so

P = d\Theta

1 × 10⁻⁹ =  2 × 10⁻⁹  × d

d = (1 × 10⁻⁹) / (2 × 10⁻⁹)  

d = 0.5 m

Also Let \Theta_{3} = 3 nC

so

P = d\Theta

1 × 10⁻⁹ =  3 × 10⁻⁹  × d

d = (1 × 10⁻⁹) / (3 × 10⁻⁹)

d = 0.33 m

such that;

charge                 distance

1 nC                        1.00 m      

2 nC                       0.50 m

3 nc                        0.33 m

4 nC                       0.25 m

5 nC                       0.20 m      

5 0
3 years ago
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