Answer:
3.33, 4.84
Explanation:
A) Actual coefficient of performance can be calculated by the formula stated below
Actual COP = heat delivered/ work required
Actual COP = 2,000/600
Actual COP = 3.33
B) Th = High temperature = 80°C + 273 = 353K
Tl = Low temperature = 7°C + 273 = 280K
The theoretical maximum coefficient of performance can ve calculated by the formula
Theoretical COP = Th/(Th-Tl)
Theoretical COP = 353/(353-280)
Theoretical COP = 353/73
Theoretical COP = 4.84
Answer:
Explanation:
String theory proposes that the fundamental constituents of the universe are one-dimensional “strings” rather than point-like particles. String theory also requires six or seven extra dimensions of space, and it contains ways of relating large extra dimensions to small ones. In statistical mechanics, entropy is an extensive property of a thermodynamic system. It quantifies the number Ω of microscopic configurations that are consistent with the macroscopic quantities that characterize the system theyre related It later developed into superstring theory, which posits a connection called supersymmetry between bosons and the class of particles called fermions. Five consistent versions of superstring theory were developed before it was conjectured in the mid-1990s that they were all different limiting cases of a single theory in 11 dimensions known as M-theory. In late 1997, theorists discovered an important relationship called the AdS/CFT correspondence, which relates string theory to another type of physical theory called a quantum field theory.
White dwarfs<span> are formed from the collapse of low mass </span>stars<span>, less than about 10 time the mass of the Sun. This </span>star<span> loses most of its mass in a wind, leaving behind a core that is less than 1.44 solar mass. On the other hand,</span>neutron stars<span> are formed in the catastrophic collapse of the core of a massive </span>star.
Answer:
(a) Elongation of the rod==5.61×10⁻⁹m
(b) Change in diameter=1.640×10⁻⁸m
Explanation:
Given data
Diameter d=78 in=1.9812 m
Cross Area is:
Applied Load P=17 KN=17×10³N
E=29 × 106 psi=1.99947961×10¹¹Pa
Stress and Strain in x direction
Stress in x direction
σ=P/A
σ=5517.25 Pa
Strain in x direction
ε=σ/E
ε=2.76×10⁻⁸
Part (a)
Elongation of the rod=Lε
=(0.2032)(2.76×10⁻⁸)
Elongation of the rod==5.61×10⁻⁹m
Part(b) Change in diameter
Strain in y direction
ε₁= -vε
ε₁= -(0.30)(2.76×10⁻⁸)
ε₁=-8.28×10⁻⁹
Change in diameter=d×ε₁
Change in diameter=(1.9812m)×(-8.28×10⁻⁹)
Change in diameter=1.640×10⁻⁸m
