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AfilCa [17]
3 years ago
9

What are some guidelines for using self-assessments?

Physics
2 answers:
lakkis [162]3 years ago
4 0
Decide which components you wish to assess yourself. There is no set order in which you do this. you could, for an example assess one or two elements and skip the rest.
Dmitriy789 [7]3 years ago
3 0

Answer:

Few guidelines which are choosing for the personal self assessments, that work for your best and raise your health standards, instead of others doing this on the behalf of yours.

Explanation:

There are some guidelines which are discussed below for using self assessments.

  • The observer can learn to organize his learning autonomously.
  • The observer can motivate himself in that way that will work for him.
  • The observer should be aware of his motivational learning and can rely on that.
  • He can re motivate himself again after knowing that his initial motivation is growing thin.
  • He can motivate himself to learn something which are good for his personal growth and development.
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A 75 A resistor in a circuit has a current flowing through it of 2.0 A. What is
Reptile [31]

Answer:

The power dissipated by the resistor can be calculated as P = I^{2} R .

Explanation:

  • Joules heating law states that any conductor passed with the electric current produces heating effect which is the electric power loss.
  • The given circuit has, R = 75 ohm resistor (the unit is wrong i question because resistor's unit is ohm not Ampere).
  • Current flowing through the circuit is I = 2.0 A.
  • By using joules heating theory, P = I^{2} R,

                  or,   P = 2^{2} * 75

                  or,   P= 4*75

                 or,  P= 300 W.

  • So the power dissipated by the resistor in the circuit is 300 W.
7 0
3 years ago
Una muestra de agua (líquida) de 1220 kg se encuentra a 0° C y baja se temperatura hasta -29°C mientras se congela en el proceso
S_A_V [24]

Answer:

-148,6 MJ

Explanation:

Dado que la liberación de calor al medio ambiente es;

H = mcθ

Dónde;

m = masa de agua

c = capacidad calorífica específica del agua

θ = aumento de temperatura

H = 1220 kg × 4200 × [-29-0]

H = -148,6 MJ

5 0
3 years ago
Suppose the Sun were suddenly to shrink in size but that its mass remained the same. According to the law of conservation of ang
labwork [276]

I think its angular velocity would increase

8 0
4 years ago
The titanium shell of an SR-71 airplane would expand when flying at a speed exceeding 3 times the speed of sound. If the skin of
Fed [463]

Answer:

The 10-meter long rod of an SR-71 airplane expands 0.02 meters (2 centimeters) when plane flies at 3 times the speed of sound.

Explanation:

From Physics we get that expansion of the rod portion is found by this formula:

\Delta l = \alpha\cdot l_{o}\cdot (T_{f}-T_{o}) (Eq. 1)

Where:

\Delta l - Expansion of the rod portion, measured in meters.

\alpha - Linear coefficient of expansion for titanium, measured in \frac{1}{^{\circ}C}.

l_{o} - Initial length of the rod portion, measured in meters.

T_{o} - Initial temperature of the rod portion, measured in Celsius.

T_{f} - Final temperature of the rod portion, measured in Celsius.

If we know that \alpha = 5\times 10^{-6}\,\frac{1}{^{\circ}C}, l_{o} = 10\,m, T_{o} = 0\,^{\circ}C and T_{f} = 400\,^{\circ}C, the expansion experimented by the rod portion is:

\Delta l = \left(5\times 10^{-6}\,\frac{1}{^{\circ}C} \right)\cdot (10\,m)\cdot (400\,^{\circ}C-0\,^{\circ}C)

\Delta l = 0.02\,m

The 10-meter long rod of an SR-71 airplane expands 0.02 meters (2 centimeters) when plane flies at 3 times the speed of sound.

4 0
3 years ago
What is the resistance of 1.0 m of a solid cylindrical metal cable having a diameter of 0.40 inches and a resistivity of 1.68 ×
Dahasolnce [82]

Given;

redistivity =1.68/100000000W.m

diameter =0.40in

=0.01016m

length =1m

resistance =?

redistivity =resistance×area/lenght

restance=resistivity × length /area

so, resistance =1.6535/1000000 ohmn

8 0
3 years ago
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