Answer:
(a) The resistance of 25m of wire is 3 ohms
(b) the length of this wire that has resistance 22 ohms is 183.33 m
Explanation:
Given;
resistivity of the wire, ρ = 0.12 ohms per meter
(a) The resistance of 25m of wire is calculated as follows;
![R = \rho L\\\\R = 0.12 \ \frac{ohms}{m} \times 25\ m\\\\R = 3 \ ohms](https://tex.z-dn.net/?f=R%20%3D%20%5Crho%20L%5C%5C%5C%5CR%20%3D%200.12%20%5C%20%5Cfrac%7Bohms%7D%7Bm%7D%20%5Ctimes%2025%5C%20m%5C%5C%5C%5CR%20%3D%203%20%5C%20ohms)
(b) the length of this wire that has resistance 22 ohms is calculated as;
![L = \frac{R}{\rho} \\\\L = \frac{22 \ ohms }{0.12 \ ohms/m} = 183.33 \ m](https://tex.z-dn.net/?f=L%20%3D%20%5Cfrac%7BR%7D%7B%5Crho%7D%20%5C%5C%5C%5CL%20%3D%20%5Cfrac%7B22%20%5C%20ohms%20%7D%7B0.12%20%5C%20ohms%2Fm%7D%20%3D%20183.33%20%5C%20m)
Answer:
F₁ / F₂ = 10
therefore the first out is 10 times greater than the second barrier
Explanation:
For this exercise let's use the relationship between momentum and momentum.
I = F t = Δp
in this case the final velocity is zero
F t = 0 -m v₀
F = m v₀ / t
in order to answer the question we must assume that the two vehicles have the same mass and speed
concrete barrier
F₁ = -p₀ / 0.1
F₁ = - 10 p₀
barrier collapses
F₂ = -p₀ / 1
let's look for the relationship of the forces
F₁ / F₂ = 10
therefore the first out is 10 times greater than the second barrier
The mechanical advantage of a machine is the ratio of the force produced by the machine to the force applied to it. Therefore, we may calculate the applied force using:
Mechanical advantage = force by machine / force applied
6 = 2 / force applied
Force applied = 1/3
Thus, the distance that the effort must move will be 1/3 inch