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fenix001 [56]
3 years ago
15

What determines if a star turns into a red giant or a red supergiant?

Physics
1 answer:
mixer [17]3 years ago
3 0

Answer:

Explanation:

As stars age, they evolve away from the main sequence to become red giants or supergiants. The core of a red giant is contracting, but the outer layers are expanding as a result of hydrogen fusion in a shell outside the core. The star gets larger, redder, and more luminous as it expands and cools.

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i thinks answers is gap relutance increases linearly with magnetic density

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4 years ago
I forgot this someone help
dexar [7]

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A. water + carbon dioxide + sunlight = oxygen + <u>glucose </u><u>!</u>

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2 years ago
Which example would most likely decrease friction?
andreev551 [17]

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using cleats other than gym shoes

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3 years ago
Explain what is meant by “field” and compare the properties of gravitational, electric, and magnetic forces in terms of particle
notsponge [240]
Field in this context refers to a region of the space to which corresponds a value.

There is a gravitational field around the earth, because a mass m placed at any point around the earth will be atracted (gravitational force) by it.

There is an electric field in a point when a charge placed there feels an electric force.

The gravitational field is proportional to the value of the mass of the object that produces it.

The electric field is proportional to the magnitude of the charge of the particle that produces it.

The gravitational field is always attractive. The electric field may be attractive or repulsive.

Both fields are proportional to the inverse of the squared distance.

The magnetic field is created when a charge is in movement,i.e a charge in movement will create a magnetid fiedl around it that will act and create a magnetic force over other charge also in movement.

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6 0
3 years ago
Rebecca heated 50mL of water from 0 degrees Celsius to 60 degrees Celsius. How much energy did she use to heat the water? Rememb
kramer

Answer:

12552 J or 3000 calories

Explanation:

Q = m × c × ∆T

Where;

Q = amount of heat energy (J)

m = mass of water (g)

c = specific heat capacity (4.184 J/g°C)

∆T = change in temperature

For 50mL of water, there are 50g, hence, m = 50g, c = 4.184 J/g°C, initial temperature = 0°C, final temperature = 60°C.

Q = m × c × ∆T

Q = 50 × 4.184 × (60 - 0)

Q = 209.2 × 60

Q = 12552 J

Hence, the amount of heat energy used to heat the water is 12552 J or 3000 calories

3 0
3 years ago
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