Scientists often work on projects for a long time and fail to see sources of error in their research. Which process allows an ou
1 answer:
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Answer:
= 17º C
Explanation:
This is a calorimetry problem, where heat is yielded by liquid water, this heat is used first to melt all ice, let's look for the necessary heat (Q1)
Let's reduce the magnitudes to the SI system
Ice m = 80.0 g (1 kg / 1000 g) = 0.080 kg
L = 3.33 105 J / kg
Water M = 860 g = 0.860 kg
= 4186 J / kg ºC
Q₁ = m L
Q₁ = 0.080 3.33 10⁵
Q₁ = 2,664 10⁴ J
Now let's see what this liquid water temperature is when this heat is released
Q = M ΔT = M
(T₀₁ -
)
Q₁ = Q
= T₀₁ - Q / M ce
= 26.0 - 2,664 10⁴ / (0.860 4186)
= 26.0 - 7.40
= 18.6 ° C
The initial temperature of water that has just melted is T₀₂ = 0ª
The initial temperature of the liquid water is T₀₁= 18.6
m
+ M
= M
T₀₁ - m
T₀₂o2
= (M To1 - m To2) / (m + M)
= (0.860 18.6 - 0.080 0) / (0.080 + 0.860)
= 17º C
gg
Answer:
1.63
Explanation:
The equation would be used where:
g = acceleration due to gravity
G = universal gravitational constant (6.67408 ×
)
M = mass
R = radius.
assuming the values following both 10s of the mass and radius are their exponents, which is a little confusing, the values given would simply be substituted.
Anyone can correct me if I'm wrong.
Answer:
W'=125.44 N
Explanation:
The weight of a person on the surface of Earth is 784 N
Weight is given by :
W = mg
m is mass of the person and g is acceleration due to gravity on the surface of Earth (10 m/s²)
The acceleration due to gravity on the surface of Moon, g' = 1.6 m/s²
Weight of the person on the moon is :
W'=mg'
Hence, the person would weigh 125.44 N on the Moon.