The nature of the image is magnified , virtual , and upright.
<h3>Further explanation</h3>
We will solve this problem using following formula:
where:
<em>so = distance of object from mirror</em>
<em>si = distance of image from mirror</em>
<em>f = focal length of mirror</em>
<u>Given:</u>
Magnification = M = 1
Initial Image Distance = si = 30 cm
Difference of Object's Distance = Δso = 20 cm
<u>Unknown:</u>
Final Image Distance = si' = ?
<u>Solution:</u>
<h3>
Initial Condition:</h3>
<h3>Final Condition:</h3>
Because si' < 0 , the nature of the image will be magnified , virtual , and upright.
<h3>Learn more</h3>
<h3>Answer details</h3>
Grade: High School
Subject: Physics
Chapter: Light
Keywords: Light , Mirror , Magnification , Ray , Diagram , Image , Real , Virtual