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kiruha [24]
3 years ago
10

Newton’s Laws of Motion are absolute in classical physics. One example that uses all three laws simultaneously is the firing of

a rocket in space. Hollywood uses this idea when they use fire extinguishers, or a rocket, in space to move about. Write a brief essay describing how Newton’s Laws explain how a rocket in space can move objects. Be sure to touch on each law within your essay.
Physics
2 answers:
inysia [295]3 years ago
5 0

Explanation:

Since there is no medium in space we need rockets as they can travel without any medium. They release the the thrust from the nozzle (which is action) and an equal and opposite force acts on the nozzle (which is reaction) to move it forward. This is as per the third law of motion (<em>Action Reaction Principle</em>) which states that every action has an equal and opposite reaction.

As per the second law of motion, the acceleration of an object depends on its mass and force applied on it. As the rocket moves it discards its unused parts which makes it lighter. Also the decreasing amount of fuel further reduces the mass. Both of these factors increases the acceleration of the rocket.

As per the first law of motion, <em>law of Inertia</em>, an object will not change its state of motion until an unbalanced force is applied on it. So, if the rocket is moving at a speed of x Km/h and we shut down the engine, it will keep moving at the same speed without using any extra fuel.

Ksju [112]3 years ago
4 0
Action and reaction are the rocket fuel going backwards and the rocket going forward. 3
f=ma 2
the rocket was at rest, 1, until there was a resultant external force 1 at which point 2 came in, with 3 alongside
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Queremos un cilindro de simple efecto que utilice en su funcionamiento un volumen de aire a presión atmosférica de 13,122 litros
zhuklara [117]

Answer:

1) El diámetro es de aproximadamente 913,987 cm.

2) La fuerza del cilindro es 5576850 kgf

Explanation:

1) Los parámetros dados son;

El volumen del aire = 13,122 litros = 13122000 cm³

La presión de trabajo = 8.5 kgf / cm²

La longitud del cilindro = 20 cm.

Por lo tanto, tenemos;

El área de la base del cilindro = π · r² = 13122000 cm³ / (20 cm) = 656100 cm²

r = √ (656100 / π) ≈ 456,994 cm

El diámetro = 2 × r ≈ 2 × 456.994 ≈ 913.987 cm

El diámetro ≈ 913,987 cm

2) La fuerza del cilindro = El área de la base del cilindro × La presión de trabajo

∴ La fuerza del cilindro = 656100 cm² × 8.5 kgf / cm² = 5576850 kgf

La fuerza del cilindro = 5576850 kgf

3 0
2 years ago
What is the average (mean) of these numbers: 13,43, 12, 3,66​
algol13

Answer:

27.4

Explanation:

(13+43+12+3+66)/5

137/5

27.4

3 0
3 years ago
Read 2 more answers
Select the correct answer.
spin [16.1K]

Answer:

There isnt enough in your question to answer the question bro, like we need a picture or something bro.

Explanation:

7 0
3 years ago
What is the wavelength associated with 0.113kg ball traveling with velocity of 43 m/s?
lesya [120]

Answer:

2.73×10¯³⁴ m.

Explanation:

The following data were obtained from the question:

Mass (m) = 0.113 Kg

Velocity (v) = 43 m/s

Wavelength (λ) =?

Next, we shall determine the energy of the ball. This can be obtained as follow:

Mass (m) = 0.113 Kg

Velocity (v) = 43 m/s

Energy (E) =?

E = ½m²

E = ½ × 0.113 × 43²

E = 0.0565 × 1849

E = 104.4685 J

Next, we shall determine the frequency. This can be obtained as follow:

Energy (E) = 104.4685 J

Planck's constant (h) = 6.63×10¯³⁴ Js

Frequency (f) =?

E = hf

104.4685 = 6.63×10¯³⁴ × f

Divide both side by 6.63×10¯³⁴

f = 104.4685 / 6.63×10¯³⁴

f = 15.76×10³⁴ Hz

Finally, we shall determine the wavelength of the ball. This can be obtained as follow:

Velocity (v) = 43 m/s

Frequency (f) = 15.76×10³⁴ Hz

Wavelength (λ) =?

v = λf

43 = λ × 15.76×10³⁴

Divide both side by 15.76×10³⁴

λ = 43 / 15.76×10³⁴

λ = 2.73×10¯³⁴ m

Therefore, the wavelength of the ball is 2.73×10¯³⁴ m.

8 0
3 years ago
What's the equivalent resistance to the resistances shown?<br><br>A) 5<br>B) 6<br>C) 2<br>D) 3
PIT_PIT [208]
From A to B its 5 ohm.
above shown 6 and 12 ohm resistors are in parallel to short circuit hence their equivalent resistance is zero.
(Current doesnt flow through a resisstor if there is a Short circuit alternate.
6 0
2 years ago
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