Answer:
Infrared photons carry lower radiation energy than the visible light.
Explanation:
- Each photon carries an energy that is directly proportional to its frequency, being this proportionality constant the Planck's constant h.
- So, we can write the energy of a single photon as follows:
- Since there exists an inverse relationship between wavelength and frequency, and infrared radiation has longer wavelengths, this means that its frequency is lower than the one of the visible light.
- So, an infrared photon carries less energy that one of the visible light.