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liberstina [14]
3 years ago
12

Goals can be big or small? Question 1 options: True False

Physics
1 answer:
pav-90 [236]3 years ago
7 0

Answer:

Probably big

Explanation:

lol

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Identify each of the cell structures in the figure
nexus9112 [7]
Fair enough ! Where's the figure ?
3 0
3 years ago
Answer????????????????????????
Keith_Richards [23]

Answer:

The atoms of noble gases already have complete outer shells

Explanation:

so they have no tendency to lose, gain, or share electrons. This is why the noble gases are inert and do not take part in chemical reactions. ... atoms of group 0 elements have complete outer shells (so they are unreactive)

3 0
3 years ago
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An object is 50 cm from a converging lens with a focal length of 40 cm . A real image is formed on the other side of the lens, 2
Leno4ka [110]

Answer:

d) -4.0

Explanation:

The magnification of a lens is given by

M=-\frac{q}{p}

where

M is the magnification

q is the distance of the image from the lens

p is the distance of the object from the lens

In this problem, we have

p = 50 cm is the distance of the object from the lens

q = 250 cm - 50 cm is the distance of the image from the lens (because the image is 250 cm from the obejct

Also, q is positive since the image is real

So, the magnification is

M=-\frac{200 cm}{50 cm}=-4.0

7 0
3 years ago
Durning which type of process does pressure remain consistent
Simora [160]

Answer:

\fbox {D. Isobaric}

Explanation:

The process during which pressure remains constant is called an isobaric process.

6 0
3 years ago
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A quarterback throws releases a 400. g football 1.2 meters off of the ground with a speed of 25 m/s. Determine the total energy
Usimov [2.4K]
Kinetic energy is an expression of the fact that a moving object can do work on anything it hits; it quantifies the amount of work the object could do as a result of its motion. And potential energy <span>is the </span>energy<span> that is stored in an object due to its position relative to some zero position. </span><span> We calculate as follows:

KE + PE = mv^2 / 2 + mgh 
Total energy = .4(25)^2/2 + .4(9.81)(1.2)
Total energy = 129.71 J = 130 J <------- OPTION A</span>
4 0
3 years ago
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