The transition zone between the crust and mantle is called as mohorovicic discontinuity.
The mohorovicic discontinuity was discovered by Andrija Mohorovicic in the year of 1909. The Moho lies at the depth of 35km beneath the continents and 8km beneath the oceanic crust. The Moho separates both the continental crust and the oceanic crust from underlying mantle. The Moho lies almost entirely within the lithosphere, only beneath the Mid Oceanic Ridge does it define lithosphere and asthenosphere boundary. Immediate above the Moho velocity of the P wave is 6km/sec and just below the Moho it becomes 8km/sec. Moho is characterised by up to 500km thick.
The Mohorovicic Discontinuity marks the lower limit of Earth's crust. It occurs at an average depth of about 8 kilometers beneath the ocean basins and 32 kilometers beneath continental surfaces. Mohorovicic was able to use his discovery to study thickness variations of the crust.
Mohorovicic discontinuity is the layer which is between the earth's crust and mantle. It's density ranges from 3.3 to 3.7.
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Explanation:
If the intensity of the yellow light increased, meaning more photons will strike the Potassium metal per unit area. This will cause more ejection of electrons from the metal and hence, the strength of current will also increase as we know that
I = Q/t, as the charge increase , the current will also increase.
Answer:
impulse = force * time = 20 * 10 = 200 Ns
change in momentum = impulse = 200 kgm/s
Answer:
Explanation:
In a rotating system , when a torque is applied , angular acceleration or deceleration takes place . The child is walking towards the center . He must be applying force on the ground . In return , ground must be applying reaction force on him which helps him to go towards the center . These two force of action and reaction are internal forces . One will increase the angular momentum of one and the other force will decrease the angular
momentum of other . But total angular momentum of the whole system will remain constant . So angular momentum will be conserved.
Answer:
work done is = 0
Explanation:
given data
distance = 2 cm
potential = 1 V
charge with magnitude = 1 nC
to find out
work done by the electrostatic force
solution
we know that at equipotential surface is that surface which have equal potential at each every point that we say
work done will be
work done = ∫dw
∫dw =
here q is charge
so
net work done = q ( v2 - v1 )
and
so v2 = v1 = 0
so
work done is = 0