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3 years ago

WILL GIVE BRAINLYEST!!!!!!!!!!!!

Physics

2 answers:

lakkis [162]3 years ago

6 0

I would say it would be the weight read.

Only because the Control is the type of liquid and the constants are Size of object and amount of liquid

Eva8 [605]3 years ago

4 0

Answer:

the amount of liquid in which the object was submerged

Explanation:

As we know that spring balance will read the spring force that is exerted by spring on the object

Now when the object is suspended by the spring then in that case the spring force is balanced by the weight so spring will read the correct mass of the object.

Now the object is suspended by the spring and then submerged into the liquid so in that case we can say

$F_{spring} + F_b = mg$

$F_{spring} = mg - \rho_{liquid}Vg$

so here the reading will be less and it depends on volume of object and density of liquid

so independent variable will be

the amount of liquid in which the object was submerged

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AnnZ [28]

First, calculate the work done: 54 x 10 = 540J.
Now calculate power: 540 / 6 = 90.
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7 0

3 years ago

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A boat is travelling due west at a speed of 47 miles per hour. If the boat started off 170 miles directly north of the city of S

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3 years ago

Differentiate scalar & vector quantity?

Keith_Richards [23]

$\textbf{Hello Friend}$

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5 0

3 years ago

A 2.31 kg rope is stretched between supports 10.4 m apart. If one end of the rope is tweaked, how long will it take for the resu

zlopas [31]

Answer:

t = 0.657 s

Explanation:

First, let's use the appropiate equations to solve this:

V = √T/u

This expression gives us a relation between speed of a disturbance and the properties of the material, in this case, the rope.

Where:

V: Speed of the disturbance

T: Tension of the rope

u: linear density of the rope.

The density of the rope can be calculated using the following expression:

u = M/L

Where:

M: mass of the rope

L: Length of the rope.

We already have the mass and length, which is the distance of the rope with the supports. Replacing the data we have:

u = 2.31 / 10.4 = 0.222 kg/m

Now, replacing in the first equation:

V = √55.7/0.222 = √250.9

V = 15.84 m/s

Finally the time can be calculated with the following expression:

V = L/t ----> t = L/V

Replacing:

t = 10.4 / 15.84

t = 0.657 s

4 0

3 years ago

A powerful motorcycle can produce an acceleration of 3.00 m/s2 while traveling at 90.0 km/h. At that speed the forces resisting

nata0808 [166]

Answer:

1185 N

Explanation:

From Newton’s second law of motion,

F=ma where m= mass of motorcycle, a is acceleration of the motorcycle and F=Force

Net force acting on motorcycle $F_{net}$ is given by $F_{net}=F-f$

Where F is force acting on motorcycle and f is frictional force

Substituting F-f for $F_{net}$

$F_{net}=ma$ hence ma= F- f Substituting a with 3, m with 245Kg and f with 450N as provided

245*3= F- 450

F=245*3 +450= 1185 N

6 0

3 years ago