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Llana [10]
3 years ago
8

Considera que en tu casa tienes un televisor de 110 W, si pasa encendido 4 horas diarias, Cuál será la energía consumida durante

un mes (30 días). ¿Cuál es el costo de funcionamiento si el precio de kWh es de 9 centavos
Physics
2 answers:
Inessa05 [86]3 years ago
8 0

Answer:

a) 13.2kWh

b) 118800 cents

Explanation:

(a) To find the energy consumed during one month you use the following formula:

E=Pt    (1)

E: energy consumed

P: power of the tv (energy consumed per hour) = 110 W

t: time

The tv is on for four hours per day. You first calculate the number of hours, in which the tv is on, for one month:

t=4\frac{h}{day}*\frac{30day}{1month}=120\frac{h}{month}

Then, the tv is on 120 h on a month.

Next, you replace the values of P ant t in the equation (1) for E:

E=(110W)(120h)=13200Wh=13.2\ kWh

(b) If the price for kWh is 9 cents you have for the tv:

COST=13.2kWh*\frac{9cents}{1kWh}=118800\ cents

hence, the cost of the energy consumed  by the  tv is 118800 cents in on month

rjkz [21]3 years ago
4 0

Answer:

 E = 13.2 kWh

,     Cost = $ 10.8

Explanation:

We can look for the consumed energy from the expression of the power

      P = W / t

The work is equal to the variation of the kinetic energy, for which

       P = E / t

       E = P t

       

look for the energy consumed in one day and multiply by the days of the month in the month

      E = 110 4 30

      E = 13200 W h

       E = 13.2 kWh

the cost of this energy is

    Cost = 0.9 12

    Cost = $ 10.8

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The acceleration of a rocket engine is given here, and after 50 seconds of flight, the engine fails, and we must determine the altitude of the rocket at the time the engine fails.  Because the rocket starts from rest, the time taken is 50 seconds, the initial velocity is zero, and the acceleration is 22.9 meters per second square. So we use the kinamatics equation s equal to v. I t plus half 8 square. There is no acceleration at the start. 22.9 and t is 50 seconds, so displacement 2.86 times 10 to the power 4 is met. This is the rocket's displacement in 50 seconds, so this is the rocket's altitude when the engine fails.

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Two particles A and B start simultaneously from a Point P with velocities 20 m/s and 30 m/s respectively. A and B move with acce
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Answer:

<u>20 m/s</u>

Explanation:

<u>Given</u>

  • u(A) = 20 m/s
  • u(B) = 30 m/s
  • acceleration equal in magnitude but opposite in direction

<u>Solving</u>

  • Velocity of A at Q = 30 m/s
  • From, P to Q, <u>Δv(A) = 30 - 20 = +10 m/s</u>
  • Therefore, velocity of B at Q will be decreased by 10 as it is equal in magnitude but opposite in direction to A
  • Δv(B) = v(B at Q) - u(B at P)
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Calculate the pressure exerted on the floor by the boy standing on both feet if the weight of the boy is 40kg. Assume that the a
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Answer:

P = 1333.33 N

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The pressure exerted by the boy on the floor can be calculated by the following equation:

P = \frac{F}{A}

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A = Area of application of force = 2(Area of one show) = 2(6 cm x 25 cm)

A = 2(0.06 m x 0.25 m) = 0.03 m²

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frozen [14]

Answer:

1.53 seconds

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