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Llana [10]
3 years ago
8

Considera que en tu casa tienes un televisor de 110 W, si pasa encendido 4 horas diarias, Cuál será la energía consumida durante

un mes (30 días). ¿Cuál es el costo de funcionamiento si el precio de kWh es de 9 centavos
Physics
2 answers:
Inessa05 [86]3 years ago
8 0

Answer:

a) 13.2kWh

b) 118800 cents

Explanation:

(a) To find the energy consumed during one month you use the following formula:

E=Pt    (1)

E: energy consumed

P: power of the tv (energy consumed per hour) = 110 W

t: time

The tv is on for four hours per day. You first calculate the number of hours, in which the tv is on, for one month:

t=4\frac{h}{day}*\frac{30day}{1month}=120\frac{h}{month}

Then, the tv is on 120 h on a month.

Next, you replace the values of P ant t in the equation (1) for E:

E=(110W)(120h)=13200Wh=13.2\ kWh

(b) If the price for kWh is 9 cents you have for the tv:

COST=13.2kWh*\frac{9cents}{1kWh}=118800\ cents

hence, the cost of the energy consumed  by the  tv is 118800 cents in on month

rjkz [21]3 years ago
4 0

Answer:

 E = 13.2 kWh

,     Cost = $ 10.8

Explanation:

We can look for the consumed energy from the expression of the power

      P = W / t

The work is equal to the variation of the kinetic energy, for which

       P = E / t

       E = P t

       

look for the energy consumed in one day and multiply by the days of the month in the month

      E = 110 4 30

      E = 13200 W h

       E = 13.2 kWh

the cost of this energy is

    Cost = 0.9 12

    Cost = $ 10.8

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Mariana [72]

Answers:

a) 2.82(10)^{21} kg

b) 1410 J

c) 36.62 m/s

Explanation:

<h3>a) Mass of the continent</h3>

Density \rho  is defined as a relation between mass m and volume V:

\rho=\frac{m}{V} (1)

Where:

\rho=2720 kg/m^{3} is the average density of the continent

m is the mass of the continent

V is the volume of the continent, which can be estimated is we assume it as a a slab of rock 5300 km on a side and 37 km deep:

V=(length)(width)(depth)=(5300 km)(5300 km)(37 km)=1,030,330,000 km^{3} \frac{(1000 m)^{3}}{1 km^{3}}=1.03933(10)^{18} m^{3}

Finding the mass:

m=\rho V (2)

m=(2720 kg/m^{3})(1.03933(10)^{18} m^{3}) (3)

m=2.82(10)^{21} kg (4) This is the mass of the continent

<h3>b) Kinetic energy of the continent</h3>

Kinetic energy K is given by the following equation:

K=\frac{1}{2}mv^{2} (5)

Where:

m=2.82(10)^{21} kg is the mass of the continent

v=4.8 \frac{cm}{year} \frac{1 m}{100 cm} \frac{1 year}{365 days} \frac{1 day}{24 hours} \frac{1 hour}{3600 s}=1(10)^{-9} m/s is the velocity of the continent

K=\frac{1}{2}(2.82(10)^{21} kg)(1(10)^{-9} m/s)^{2} (6)

K=1410 J (7) This is the kinetic energy of the continent

<h3>c) Speed of the jogger</h3>

If we have a jogger with mass m=77 kg and the same kinetic energy as that of the continent 1413 J, we can find its velocity by isolating v from (5):

v=\sqrt{\frac{2 K}{m}} (6)

v=\sqrt{\frac{2 (1413 J)}{77 kg}}

Finally:

v=36.62 m/s This is the speed of the jogger

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Explanation:

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Answer:

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