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Over [174]
3 years ago
12

A fission reaction is one in which the weaker electrostatic repulsion force wins out over the ___________ nuclear force and, as

a result, one large nucleus creates two smaller nuclei and releases energy. A) electromagnetic B) strong C) subatomic D) weak
ANSWER IS (B) STRONG
Physics
2 answers:
goblinko [34]3 years ago
8 0
The strong nuclear force is responsible for holding nuclei together
Snezhnost [94]3 years ago
8 0

The strong nuclear force is responsible for holding nuclei together....

You might be interested in
If a particle undergoes shm with amplitude 0.21 m, what is the total distance it travels in one period?
Ymorist [56]
If a particle undergoes simple harmonic motion with an amplitude of 0.21 meters, this means that the maximum displacement of the particle from its resting position is 0.21. For one period, it traveled from its starting position which is twice the amplitude and then back to its original position which is another distance that is twice the amplitude as well. Therefore, the total distance it traveled is 2*amplitude + 2*amplitude = 2*0.21 + 2*0.21 = 0.42 + 0.42 = 0.84 meters.
7 0
3 years ago
The total blood volume of a human is 75 ml/kg. If the volumetric flow rate is the same in adults and children, how much more blo
Tema [17]

The amount of blood that flows through the venae cavea of the adult is 3750 ml more than that of the child.

<h3>What is flow rate?:</h3>

This is the volume of fluid flowing in a vessel per unit time.

First, we need to get the volume of blood flowing through the venae cavae of the adult and the child in 1 hour, then subtract the volume of blood for the child from that of the adult.

Using,

  • V = F'm................ Equation 1

Where:

  • V = Volume of the blood
  • F' = Flow rate
  • m = mass of blood.

For the Adult,

Given:

  • m = 70 kg
  • F = 75 ml/kg

Substitute these values into equation 1

  • V = 70(75)
  • V = 5250 ml.

For the child,

Given:

  • m = 20 kg
  • F = 75 ml/kg

Substitute these values into equation 1 also

  • V = 75(20)
  • V = 1500 ml.

The amount of blood that flows more through the adult than the child is

  • A = 5250-1500
  • A = 3750 ml.

Hence, the amount of blood that flows through the venae cavea of the adult is 3750 ml more than that of the child.

Learn more about flow rate here: brainly.com/question/21630019

5 0
2 years ago
If 5000Pa a pressure is exerted on an object with the contact area 0.04m^2. Calculate the mass of an object
Whitepunk [10]
  • Pressure = 5000 Pa
  • Contact Area = 0.04 m^2
  • Acceleration due to gravity = 9.8 m/s^2
  • Let the force be F.
  • We know, Force = Pressure × Contact Area
  • Therefore, Force = 5000 Pa × 0.04 m/s^2
  • or, Force = 200 N
  • We know, force = mass × acceleration
  • Therefore, mass = force ÷ acceleration
  • or, mass = 200 N ÷ 9.8 m/s^2 = 20.4 Kg

<u>Answer</u><u>:</u>

<u>2</u><u>0</u><u>.</u><u>4</u><u> </u><u>Kg</u>

Hope you could understand.

If you have any query, feel free to ask.

6 0
1 year ago
You throw a 3.00 N rock vertically into the air from ground level. You observe that when it is 16.0 m above the ground, it is tr
Morgarella [4.7K]

Answer:

The final speed of the stone as it lift the ground is 23.86 m/s.            

Explanation:

Given that,

Force acting on the rock, F = 3 N

Distance, d = 16 m

Initial speed of the stone, u = 22 m/s

We need to find the rock's speed just as it left the ground. It can be calculated using work energy theorem as :

W=\Delta E\\\\W=\dfrac{1}{2}m(v^2-u^2)\\\\Fd=\dfrac{1}{2}m(v^2-u^2)\\\\v^2=\dfrac{2Fd}{m}+u^2\\\\v^2=\dfrac{2mgd}{m}+u^2\\\\v^2=2\times 9.8\times 16+(16)^2\\\\v=23.86\ m/s

So, the final speed of the stone as it lift the ground is 23.86 m/s.                                                    

4 0
2 years ago
Richard is driving home to visit his parents. 150 mi of the trip are on the interstate highway where the speed limit is 65 mph .
Serggg [28]

Answer:

t = 25.5 min

Explanation:

To know how many minutes does Richard save, you first calculate the time that Richard takes with both velocities v1 = 65mph and v2 = 80mph.

t_1=\frac{x}{v_1}=\frac{150mi}{65mph}=2.30h\\\\t_2=\frac{x}{v_2}=\frac{150mi}{80mph}=1.875h

Next, you calculate the difference between both times t1 and t2:

\Delta t=t_1-t_2=2.30h-1.875h=0.425h

This is the time that Richard saves when he drives with a speed of 80mph. Finally, you convert the result to minutes:

0.425h*\frac{60min}{1h}=25.5min=25\ min\ \ 30 s

hence, Richard saves 25.5 min (25 min and 30 s) when he drives with a speed of 80mph

3 0
2 years ago
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