Answer: The correct answer is- The plant with the smooth seeds is homozygous for the dominant trait.
According to the Mendelian genetics, dominant trait is the one that expresses itself and masks the expression of the recessive trait. Dominant is depicted with capital letter and recessive with small letter.
Let us consider 'S' depicts the allele for smooth seed and 's' for the wrinkled seeds. There can be two genotypes for smooth seeds that is 'Ss' and 'SS' whereas only one genotype is possible for wrinkled ( 'ss') seeds.
As per the question, there is no chance of the offspring born with wrinkled seeds. This is only possible when the parental plant with smooth seeds is homozygous for the dominant trait ( like SS) . Therefore, only smooth trait will be visible in the offsprings ( with genotype Ss) of the parental plants and there will be no chance of wrinkled seeds (ss) in the offsprings.
Answer:
8.19m
Explanation:
Parameters given:
Pressure, P= 11.6 psi = 79979.185 Pa
Gauge pressure is given as:
P = h*d*g
=> h = P/(d*g)
Where
h = height of tank
d = density
g = acceleration due to gravity
Density of water = 997 kg/m³
Therefore, the height of the tank is:
h = 79979.185/(997 * 9.8)
h = 8.19m
The chemical symbol always begins with a capital letter.
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