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Scilla [17]
3 years ago
8

Collision Problem. Need help!

Physics
1 answer:
lukranit [14]3 years ago
7 0

Answer:

4 Km/hr

Explanation:

Data obtained from the question include the following:

Mass of ball (Mb) = 15 Kg

Velocity of ball (Vb) = 20 Km/hr

Mass skater (Ms) = 60 Kg

Velocity of skater (Vs) = 0 Km/hr

Velocity after collision (V) =..?

Thus, we can obtain the velocity after collision as follow:

MbVb + MsVs = V(Mb + Ms)

(15 x 20) + (60 x 0) = V (15 + 60)

300 + 0 = 75V

300 = 75V

Divide both side by 75

V = 300/75

V = 4 Km/hr.

Therefore, the velocity after the collision is 4 Km/hr.

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Explanation:

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The purpose of this lab is to explore the various ways to calculate projectile velocity using horizontal, vertical and angle inf
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4 years ago
A baseball m=.34kg is spun vertically on a massless string of length l=.52m. the string can only support a tension of tmax=9.9n
larisa86 [58]
<span>4.5 m/s This is an exercise in centripetal force. The formula is F = mv^2/r where m = mass v = velocity r = radius Now to add a little extra twist to the fun, we're swinging in a vertical plane so gravity comes into effect. At the bottom of the swing, the force experienced is the F above plus the acceleration due to gravity, and at the top of the swing, the force experienced is the F above minus the acceleration due to gravity. I will assume you're capable of changing the velocity of the ball quickly so you don't break the string at the bottom of the loop. Let's determine the force we get from gravity. 0.34 kg * 9.8 m/s^2 = 3.332 kg m/s^2 = 3.332 N Since we're getting some help from gravity, the force that will break the string is 9.9 N + 3.332 N = 13.232 N Plug known values into formula. F = mv^2/r 13.232 kg m/s^2 = 0.34 kg V^2 / 0.52 m 6.88064 kg m^2/s^2 = 0.34 kg V^2 20.23717647 m^2/s^2 = V^2 4.498574938 m/s = V Rounding to 2 significant figures gives 4.5 m/s The actual obtainable velocity is likely to be much lower. You may handle 13.232 N at the top of the swing where gravity is helping to keep you from breaking the string, but at the bottom of the swing, you can only handle 6.568 N where gravity is working against you, making the string easier to break.</span>
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Read 2 more answers
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